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6 N to W the L?

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Anonymous

14y ago
Updated: 8/18/2019

6 Numbers to Win the Lottery

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14y ago

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What is 6 w l n?

Could be 6 Wining Lottery Numbers.


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6 Correct numbers to win the lottery


What has the author W N L Davidson written?

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Wes and Willow went walking. What is the ratio of w's to consonants in this sentence?

There are: 5 w's 11 consonants s,n,d,l,l,n,t,l,k,n,g ratio is 5:11


What is the ratio of w's to consonants in this sentence. Wes and willow went walking?

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What are some nine letter words with 3rd letter W and 5th letter L and 7th letter N?

According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 6 words with the pattern --W-L-N--. That is, nine letter words with 3rd letter W and 5th letter L and 7th letter N. In alphabetical order, they are: downlands downlinks towelings townlands townlings towplanes


The length of a rectangle is 6 inches more than its width The perimeter of the rectangle is 24 inches What is the length of the rectangle?

P of rectangle = 2(L+W) where L=W+6 24 = 2(W+(W+6)) 12 = W+ W+ 6 6 = 2 W 3 = W The length (W+6) is 9, width (W) is 3.


How do you write algorithm to find the area of a rectangle?

You will need to define the input and times length by width.For example: L - Length & W - Widthstartsum = 0input L, Wsum = L * Wprint "The area of the rectangle is: SUM"end


A rectangle has an area of 120 square cm What are the possible dimensions?

w=3 L=40 ; w=4 L=30 ; w=2 L=60 ; w=6 L=20 ; w=5 L=24 ; etc.


What are the potion recipes for minecraft?

Here are the combinations listed: "w" = water bottle "f" = fermented spider eye "n" = nether wart "g" = glowstone dust "r" = redstone dust "m" = magma cream "l" = glistering melon "s" = spider eye "h" = ghast tear "b" = blaze powder "c" = golden carrot "u" = sugar Redstone is used to increase the duration of the potion's effects, while glowstone dust is used to increase the potency of the potion but shortening its duration, and gunpowder is used to make potions throwable Potion of Weakness: w + f Weakness extended: w + f + r Strength: w + n + b Strength Extended: w + n + b + r Strength II w + n + b + g Regeneration w + h Regeneration Extended w + n + h + r Regeneration II w + n + h + g Swiftness: w + n + u Swiftness Extended: w + n + u + r Swiftness II: w + n + u + g Slowness: w + n + u + f w + n + m + f Slowness Extended: w + n + u + f + r w + n + m + f + r Healing: w + n + l Healing II: w + n + l + g Harming: w + n + l + f w + n + s + f Harming II w + n + l + f + g w + n + s + f + g Poison: w + n + s Poison Extended: w + n + s + r Poison II: w + n + s + g Fire Resistance: w + n + m Fire Resistance Extended: w + n + m + r Night Vision: w + n + c Night Vision Extended: w + n + c + r Invisibility: w + n + c + f Invisibility Extended: w + n + c + f + r


The perimeter of a rectangle is 20 feet and the area is 24 square feet What is the width of the rectangle?

The width is 4 feet and the length is 6 feet. L + W = P/2 = 10, so L = 10 - W; L x W = 24 so W(10 - W) = 24 ie W2 - 10W + 24 = 0 This factorizes as (W - 4)(W - 6) so W = 4 and L = 6


A rectangle with the area of 6cm2 and a perimetre of 14?

Let's assume that the rectangle has length 'l' and width 'w'. The formula for the area of a rectangle is A = l × w, and the formula for the perimeter (P) of a rectangle is P = 2(l + w). We're given that the area of the rectangle is 6cm², so: A = l × w = 6cm² We're also given that the perimeter of the rectangle is 14cm, so: P = 2(l + w) = 14cm We can use the second equation to solve for one of the variables in terms of the other: l + w = 7 l = 7 - w Substituting this into the equation for the area, we get: (7 - w) × w = 6 Expanding the left side of the equation, we get: 7w - w² = 6 Rearranging and factoring, we get: w² - 7w + 6 = 0 This equation can be factored as: (w - 1)(w - 6) = 0 So, w = 1 or w = 6. If w = 1, then l = 7 - w = 6, and the perimeter would be: P = 2(l + w) = 2(6 + 1) = 14 If w = 6, then l = 7 - w = 1, and the perimeter would still be: P = 2(l + w) = 2(1 + 6) = 14 Therefore, there are two possible solutions: a rectangle with dimensions 1cm × 6cm, and a rectangle with dimensions 6cm × 1cm.