W-I-L-D- - 2012 W-I-L-D- and Out 1-7 was released on: USA: 29 October 2012
Suppose the length is L feet and the width is W feet. Then, Perimeter = 14 => 2*(L+W) = 14 or L+W=7 Also, Area = 12 => L*W=12 You could try trial and error to solve these two equations and in this particular case you will get to the answer quite quickly but for a more general method: L+W=7 => W=7-L Substituting in the second equation, L*(7-L)=12 or L^2 - 7L + 12 = 0 L^2 - 3L - 4L + 12 = 0 (L-3)*(L-4) = 0 so L=3 or L=4 But L>W and L+W = 7 so L > 3.5 so L= 4 => W=3 feet
L = w + 3L W = 28(w + 3) W = 28w2 + 3w = 28w2 + 3w - 28 = 0(w + 7) (w - 4) = 0w = -7 and W = 4L = 7
L = 14 and W = 2 would give an area (A) of 28, or 7 (L) x 4 (W) = 28 (A)
L = lengthW = widthL = W + 7andPerimeter = 2*(W + L)soPerimeter = 2*(W + (W + 7)) = 2*(2W + 7) = 4W + 14
P = 50 so L + W = 25; L = W + 7 so L = 16 cm and W = 9 cm.
Any rectangle with a length and width that multiply together to equal 14. L=14 W=1, or L=7 W=2, or L=10, w=1.4 or L=5 w=2.8 etc
area is calculated by doing length (l) times width (w). The formula is: A = l x w. if you substitute 14 for A, you get 14 = l x w. Now find the factors of 14, which are 7 and 2. put them in for l and w, and you get 14 = 7 x 2. To check your answer, simply do 7 x 2 and see if it equals 14.
The formula for the perimeter of a rectangle is 2(L + W), where L is the length and W is the width. Then 16 = 2(L + W) : 8 = L + W. And L = W - 8, or W = L - 8 So, if you were dealing integers, you can choose any two numbers between 1 and 7 so that the numbers when added equal 8.
Surface Area = 2*(L*W + W*H + H*L) = 2*(7*5 + 5*2 + 2*7) = 2*(35+10+14) = 2*59 = 118 square units.
perimeter = 2(length X width) = 2(l x w) = 2(w+7+w) - 2(2w+7)=142 2w+7 = 71; 2w=64; w = 32 and l = w+7 = 39 Check: perimeter = 2(32+37) = 142
Let the length be l, the width be w, and the area be A. The equation for the area of a rectangle is A = l*w; we know A = 77, so we need to get l in terms of w so we only have one variable to solve for. We're given l = 2w-3, so we can substitute back in: A=77=(2w-3)*w 77=2w^2-3w 0=2w^2-3w-77 0=(2w+11)*(w-7) so w=-5.5 or w=7. Since we can't have a negative width, w=7 inches. Plugging back in to our equation for l and w: l=2w-3=2(7)-3=14-3=11, so the length is 11 inches.