The fraction is 35/56.The way to find it is as follows:1) n/d = 5/82) (n-5) / (d+4) = 1/23) n = (5/8)*d [rearrange (1)]4) 2*(n-5) = (d+4) [rearrange (2)]5) 2*n - 10 = d + 4 [rearrange (4)]6) 2*n = d + 14 [rearrange (5)]7) 2*((5/8)*d) = d + 14 [substitue (3) into (6)]8) (10/8)*d = d+14 [rearrange (7)]9) (10/8)*d - d = 14 [rearrange (8)]10) (10/8)*d - (8/8)*d = 14 [rearrange (9)]11) (2/8)*d = 14 [rearrange (10)]12) d = 14 / (2/8) = 14 * 8/2 [rearrange (11)]13) d = 112/2 = 56 [simplify (12)]14) n = (5/8)*56 [substitute (13) into (3)]15) n = 280/8 = 35 [simplify (14)]16) THE ANSWER IS n/d = 35/56 [substitute (13) and (15) into the definition of the fraction]
"eating?"
I am assuming this is an arithmetic series. Use the formula nth term = a + (n-1)d where a is the 1st term, and d is the difference between each term. 10th term = 8 + (10-1)d ==>8 +9d=53 ==> 9d = 53-8 = 45 ==> d = 5 The difference is 5.
There are 22 ways to make change from a dollar using nickels, dimes, and quarters. 1. 4 q 2. 10 d 3. 20 n 4. 2 q , 5 d 5. 3 q , 2 d , 1 n 6. 1 q , 7 d, 1 n 7. 9 d, 2 n 8. 8 d, 4 n 9. 7 d, 6 n 10. 6 d , 8 n 11. 5 d , 10 n 12. 4 d , 12 n 13. 2 d , 16 n 14. 1 d , 18 n 15. 5 n , 3 q 16. 3 n , 1 q , 6 d 17. 7 n , 1 q , 4 d 18. 9 n , 1 q , 3 d 19. 11 n , 1 q , 2 d 20. 13 n , 1 q , 1 d 21. 14n , 3 d 22. 15n , 1 q
a= 5 , d= 13-5 = 8 , an= 181 an = a + (n-1) x d 181 = 5 + (n-1) x 8 181 - 5 = (n-1) x 8 176 = (n-1) x 8 176/8 = (n-1) 22 = (n-1) 22+1 = 23 n = 23 Hence, 181 is the 23rd term of the given A.P
Numbered
1. START 2. INPUT N 3. LET D=1 4. N%D? (if NO goto step 5 else goto step 6) 5. PRINT D 6. LET D=D+1 7. SQRT(N)<D? (if NO goto step 4 else goto step 8) 8. STOP
Assuming nickles, dimes, and quarters, there are ten different ways to make change for a half dollar. Just enumerate the combinations... 10 n 8 n 1 d 6 n 2 d 4 n 3 d 2 n 4 d 5 d 5 n 1 q 3 n 1 d 1 q 1 n 2 d 1 q 2 q
1. Input number, n 2. a = 0 3. d = n % 10 4. Print d 5. a = a + d 6. n = n / 10 7. If n > 0 then goto 3 8. Print a
5 Σ (3n + 5) n=1 is the sum of the first five terms of the sequence 8, 11, 14, ... which is: sum = 5/2(8 + 20) = 70 The sum of the arithmetic sequence of n terms with first term a and common difference d, ie a, a+d, a+2d, a+3d, .., a+(n-1)d, is given by: sum = number_of_terms/2(first_term + last_term) = n/2(a + a+(n-1)d) = n/2(2a + (n-1)d)
Use THE d a m n W E B. WEEB
Answer: 2008. d(n) is number of divisors of n. I give number of divisors and list them also. The divisors of n = 2008: 1, 2, 4, 8, 251, 502, 1004, 2008 d(2008) = 8 The divisors of n = 2009: 1, 7, 41, 49, 287, 2009 d(2009) = 6