9/3=3+9=12+5=17+3=20+1=21
21 Ans.............
9/3+9+5+3+1=21
3333 / 3 = 1111
1 + 3 + 11 + 33 + 101 + 303 + 1111 + 3333 = 4,896
21
150% of 2222 is 2222 + (2222 x 1/2) = 2222 + 1111 = 3333. So 150% of 2222 is 3333.
1111-2222-3333-4444
T
#include <stdio.h> int main (void) { puts ("4 1 44 11 444 111 4444 1111 000000000 444444 3333 22 1"); return 0; }
9/3 + 9+ 5+ 3+ 1
This is impossible. 21 is an odd number and all these digits are odd. Whenever you add 6 odd numbers together, the answer is always even!
1, 3, 9, 11, 33, 99, 101, 303, 909, 1111, 3333 and 9999.
(7777-6666)/1111 = 1 (4444+5555)/(9999/3333) = 3 8888/2222 = 4 4*3 + 1 =13