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A jar contains three colored marbles 10 red 15 green and 25 blue If you were to choose without looking what is the probability of selecting a blue marble?

25/50 gives the probability of selecting a blue marble


What is the probability of selecting 4 red or 5blue marbles?

The probability of selecting 4 red marbles or 5 blue marbles depends on how many marbles there are altogether, and how many of the total number of marbles are red and how many are blue.


A bag contains 3 red marbles 5 blue marbles 8 yellow marbles and 4 black marbles what is the theoretical probability of randomly picking each color marble?

The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.


A jar contains three colored marbles 10 red 15 green and 25 blue If you were to choose without looking what is the probability of selecting a green marble?

It is 15/50 = 0.3


A jar contains 11 white and 21 blue marbles a marble is drawn at random pnot blue express the probability as a fraction?

Probability of not blue is the probability of white. The probability of white is 11/(11+21) or 11/32.


What is the probability of selecting two ribbons that are not blue if there are 7 yellow 6 blue 9 red and 3 green ribbons in a drawer?

The probability is 19/25 * 18/24 = 0.57


In a bag there are 90 red counters. the probability is 0.3. how many blue counters?

To find the number of blue counters, we first determine the total number of counters in the bag. Given that the probability of selecting a red counter is 0.3 and there are 90 red counters, we can use the formula for probability: ( P(\text{Red}) = \frac{\text{Number of Red Counters}}{\text{Total Counters}} ). Rearranging, we find that the total number of counters is ( \frac{90}{0.3} = 300 ). Thus, the number of blue counters is ( 300 - 90 = 210 ).


When a jar contains 5 white marbles 3 blue marbles and 2 green marbles and if one marble is drawn at random then what is the probability that it will be blue?

There is a probability of 3 that it will be blue.


If you have been given a bag that contains 1 yellow 3 green and 4 blue marbles what is the probability of selecting green blue without replacement?

First, there are 3 greens out of 8, then 4 blues out of 7. So the probability is these two ratios multiplied: P(green, blue) = P(green/8) * P(blue/7) = (3/8) * (4/7) = 12/56 or 3/14


Is the probability that a blue marble will NOT be selected from a bag containing 9 red marbles 6 blue marbles 7 green marbles and 11 yellow marbles if one is selected randomly?

To find the probability that a blue marble will NOT be selected, first calculate the total number of marbles: 9 red + 6 blue + 7 green + 11 yellow = 33 marbles. The number of non-blue marbles is 9 red + 7 green + 11 yellow = 27 marbles. Therefore, the probability of NOT selecting a blue marble is 27/33, which simplifies to 9/11.


In a bag of candies there are 13 red candies 13 green candies 13 yellow candies and 13 blue candies. If you choose 1 candy from the bag what is the probability the candy will not be blue?

There are a total of 52 candies in the bag (13 red + 13 green + 13 yellow + 13 blue). The number of candies that are not blue is 39 (13 red + 13 green + 13 yellow). The probability of selecting a candy that is not blue is the number of non-blue candies divided by the total number of candies, which is ( \frac{39}{52} ) or ( \frac{3}{4} ).


What is the probability drawing a blue marble from a bag of 18 marblesin a bag three of which are blue?

The probability of drawing a blue marble from a bag containing 18 marbles, of which 3 are blue, is calculated by dividing the number of blue marbles by the total number of marbles. Therefore, the probability is ( \frac{3}{18} ), which simplifies to ( \frac{1}{6} ). Thus, the probability of drawing a blue marble is approximately 0.167 or 16.7%.