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A car goes from 16 m/s to 2 m/s in 3.5 s. What is the car’s acceleration?
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If A car goes from 16 ms to 2 ms in 3.5s what is the cars acceleration?
To calculate the car's acceleration, use the formula ( a = \frac{{v_f - v_i}}{{t}} ), where ( v_f ) is the final velocity, ( v_i ) is the initial velocity, and ( t ) is the time. Here, ( v_f = 2 , \text{m/s} ), ( v_i = 16 , \text{m/s} ), and ( t = 3.5 , \text{s} ). Plugging in the values: [ a = \frac{{2 , \text{m/s} - 16 , \text{m/s}}}{{3.5 , \text{s}}} = \frac{{-14 , \text{m/s}}}{{3.5 , \text{s}}} \approx -4 , \text{m/s}^2. ] Thus, the car's acceleration is approximately (-4 , \text{m/s}^2).
A car accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car’s acceleration is blankmeters/second2?
The acceleration of the body is 3 m/s²
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A car came to a stop from a speed of 16 ms in a time of 2.3 seconds. What was the acceleration of the car?
To find the acceleration of the car, we can use the formula: ( a = \frac{{\Delta v}}{{\Delta t}} ), where ( \Delta v ) is the change in velocity and ( \Delta t ) is the time interval. The initial velocity is 16 m/s and the final velocity is 0 m/s (since the car stops), so ( \Delta v = 0 - 16 = -16 , \text{m/s} ). The time interval is 2.3 seconds, thus the acceleration is ( a = \frac{{-16 , \text{m/s}}}{{2.3 , \text{s}}} \approx -6.96 , \text{m/s}^2 ).
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A car initially traveling at a speed of 16 meters per second accelerates uniformily to a speed of 20 meters per second over a distance of 36 meters what is the magnitude of her acceleration?
The average acceleration can be calculated using the formula: acceleration = (change in velocity) / (time taken). In this case, the change in velocity is 20 m/s - 16 m/s = 4 m/s and the distance is 36 meters. Since time is not provided, the acceleration cannot be determined.
