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A 110-N block on a 32 degree incline is being held motionless by friction. The coefficient of static friction between the block and the plane is .35. The force due to friction is?
Wiki User
∙ 14y ago
The force of friction is 32.65 N. The solution comes from first taking the sum of the forces in the normal. This yields the Normal force (N = Cos 32 degrees X Ff = Cos 32 X 110 N = 93.29 N) Next, we use the Normal force, plugging it into the accepted formula for Friction, Ff = u X N . This gives us: Ff = .35 X 93.29 N = 32.65 N.
Wiki User
∙ 14y ago
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How can an adjustable inclined plane be used to measure the coefficient of static friction and coefficient of static friction with a mass of 5.0?
Incline the plane until breakaway is achieved and note the angle. > A) Sin angle * 5 = force down (and parallel to) the slope in kgf. > B) Cos angle * 5 = force (weight) of block normal to slope surface. > Static friction coefficient = A / B
Why does a toy car rolling at constant speed down a straight incline track slow down when reaching the base of the incline?
i think this happens due to friction between the ground and the toy car :)
A block is at rest on an incline The force of friction necessary to prevent the block from sliding increases when the incline angle is?
increased
Do objects fall slower on an incline?
Yes, due to friction, but nothing else.
Predict the effect that significant friction would have on the acceleration of the box as it slides down the incline. Explain the cause of the predicted effect?
I have no clue.
Is the coefficient of friction on a horizontal plane between to substances the same as the coefficient of friction on the incline plane?
POMBO
Can an object move backward on an inclined plane?
Yes, if the incline angle becomes great enough. > As the angle increases, the force on the object down the incline increases but the effective weight on the slope surface decreases. > When the object breaks away the angle of incline can be used to calculate the coefficient of friction between the two surfaces. > coefficient of friction = sine ( incline angle ) / cosine ( incline angle )
The coefficient of static friction along an inclined plane is equal to tan alpha. What about the coefficient of kinetic friction?
It's not. The coefficient of static friction is only equal to the tangent of the angle of incline at the maximum angle before the object begins to slide. At this point static friction equals the component of the weight along the incline (weight X sin alpha). Static friction is given by the coefficient of static friction times the normal force (weight X cos alpha) fs = us N = us mg cos(alpha) Wx =mg sin(alpha) fs = Wx us mg cos(alpha) = mg sin(alpha) us = [sin(alpha)] / [cos(alpha)] = tan(alpha) Similarly, the coefficient of kinetic friction equals the tangent of the angle of incline only if the object is sliding down the incline at constant velocity (net force equals zero). If the object is accelerating along the incline (make this the x axis): Fnet, x = Wx - f max = mg sin(alpha) - uk mg cos(alpha) uk = [g sin(alpha) - ax] / [g cos(alpha)]
How can an adjustable inclined plane be used to measure the coefficient of static friction and coefficient of static friction with a mass of 5.0?
Incline the plane until breakaway is achieved and note the angle. > A) Sin angle * 5 = force down (and parallel to) the slope in kgf. > B) Cos angle * 5 = force (weight) of block normal to slope surface. > Static friction coefficient = A / B
When using the inclined plane what is the push or pull force?
(ignoring friction) > Mass of the object * sine (incline angle) = force down, and parallel to, the slope (kilograms force) This ratio ( force / mass) remains constant regardless of the objects mass, as long as the incline angle remains the same.
A block accelerates at 3.2 down a plane inclined at an angle 30 degrees. Acceleration of gravity is 9.8. Whats the coefficient of static friction between the block and the inclined plane?
Static friction does not apply when the block is already moving. Without friction, the force on the block parallel to the surface of the incline is Fg*sin(angle), so the acceleration without friction is 9.8* sin(30) = 9.8 * (1/2) = 4.9 Since it is accelerating at 3.2, friction is slowing down the block by (4.9-3.2 = 1.7). The coefficient of kinetic friction is (1.7/4.9) = 0.346939
How do you find the minimum coefficient of static friction for a mass on an incline of 32 degrees?
The equation for friction is F=uN. F (friction), u (coefficient of friction), and N (normal). So you first need to solve for the normal by using Newton's second law. Also solve for the x component of the gravity force. Since it is static friction, you know it should be at rest, so that x component force should be the same as the force of friction. Knowing that and the normal, plug it into the equation and solve for u.
Why does a toy car rolling at constant speed down a straight incline track slow down when reaching the base of the incline?
i think this happens due to friction between the ground and the toy car :)
A block is at rest on an incline The force of friction necessary to prevent the block from sliding increases when the incline angle is?
increased
Would friction or air pressure affect how fast a ball rolls down a incline?
Yes it would. Speed will depend on Weight of the ball, Incline angle, Friction, and air pressure.
What causes speed to increase or decrease?
Presence of friction, incline and so on.
Do objects fall slower on an incline?
Yes, due to friction, but nothing else.
