Asked in Physics
A 110-N block on a 32 degree incline is being held motionless by friction. The coefficient of static friction between the block and the plane is .35. The force due to friction is?
The force of friction is 32.65 N. The solution comes from first taking the sum of the forces in the normal. This yields the Normal force (N = Cos 32 degrees X Ff = Cos 32 X 110 N = 93.29 N) Next, we use the Normal force, plugging it into the accepted formula for Friction, Ff = u X N . This gives us: Ff = .35 X 93.29 N = 32.65 N.