Asked in Physics

A 110-N block on a 32 degree incline is being held motionless by friction. The coefficient of static friction between the block and the plane is .35. The force due to friction is?


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The force of friction is 32.65 N. The solution comes from first taking the sum of the forces in the normal. This yields the Normal force (N = Cos 32 degrees X Ff = Cos 32 X 110 N = 93.29 N) Next, we use the Normal force, plugging it into the accepted formula for Friction, Ff = u X N . This gives us: Ff = .35 X 93.29 N = 32.65 N.