Static friction does not apply when the block is already moving. Without friction, the force on the block parallel to the surface of the incline is Fg*sin(angle), so the acceleration without friction is 9.8* sin(30) = 9.8 * (1/2) = 4.9
Since it is accelerating at 3.2, friction is slowing down the block by (4.9-3.2 = 1.7). The coefficient of kinetic friction is (1.7/4.9) = 0.346939
Place the object on the plane. Slowly increase the angle of the plane until the object begins to move at angle Θ. The µs = tan Θ. For µk, same process, but give the object a little push at each increasing value of Θ.
Roll the object down an inclined plane. Adjust the angle so that the objects rolls down without sliding at a constant speed. When that happens, the tangent of the angle of the plane relative to the horizontal is the coefficient of rolling friction.
It's not. The coefficient of static friction is only equal to the tangent of the angle of incline at the maximum angle before the object begins to slide. At this point static friction equals the component of the weight along the incline (weight X sin alpha). Static friction is given by the coefficient of static friction times the normal force (weight X cos alpha) fs = us N = us mg cos(alpha) Wx =mg sin(alpha) fs = Wx us mg cos(alpha) = mg sin(alpha) us = [sin(alpha)] / [cos(alpha)] = tan(alpha) Similarly, the coefficient of kinetic friction equals the tangent of the angle of incline only if the object is sliding down the incline at constant velocity (net force equals zero). If the object is accelerating along the incline (make this the x axis): Fnet, x = Wx - f max = mg sin(alpha) - uk mg cos(alpha) uk = [g sin(alpha) - ax] / [g cos(alpha)]
He decreased the acceleration of gravity using inclined planes so it was of a value that was easily measured.
Use the formula: FsMAX=μsFN if you want to do it experimentally, get the two different surfaces, and angle one until the object on top starts moving. take the tangent of the angle that starts the objects sliding past one another, and that is your coefficient of static friction.
china
co -efficient of friction is equal to tan inverse of the inclination
smaller
(Coefficient of friction of plane ab) + 2(Coefficient of friction of plane bc) = 1 Coefficient of friction of plane ab = Coefficient of friction of plane bc = 1/3 = 0.33333......
Incline the plane until breakaway is achieved and note the angle. > A) Sin angle * 5 = force down (and parallel to) the slope in kgf. > B) Cos angle * 5 = force (weight) of block normal to slope surface. > Static friction coefficient = A / B
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Place the object on the plane. Slowly increase the angle of the plane until the object begins to move at angle Θ. The µs = tan Θ. For µk, same process, but give the object a little push at each increasing value of Θ.
If the angle is increased, the tangential component of the weight will increase, while the normal component - the one that causes friction - will decrease.
Is mgsinΘ > μmgcosΘ ? Is sinΘ > μ cosΘ ? Is sin35º > .65 cos35º Is .573 > .532 => Yes, so crate slides down the plane, no matter what the mass is or acceleration due to gravity
Yes, if the incline angle becomes great enough. > As the angle increases, the force on the object down the incline increases but the effective weight on the slope surface decreases. > When the object breaks away the angle of incline can be used to calculate the coefficient of friction between the two surfaces. > coefficient of friction = sine ( incline angle ) / cosine ( incline angle )
No, he merely decreased the acceleration of gravity using inclined planes so it was of a value that was easily measured.
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