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A 1500 kg car accelerates at 4.4 ms2 on a level stretch of road If there is a wind resistance force of 67 N what must be the frictional force between the tires and the road?
Wiki User
∙ 13y ago
The car is accelerating due to the net force acting on it which is a sum of the frictional force and wind resistance F = Fr - Fw. The net force can be found from Newton's 2nd law F = m x a and hence F = 6600 N. Since the wind acts to slow the car the frictional force must be greater than the wind and so Fr = F + Fw = 6600 + 67 = 6667. Which is alarmingly close to the Devil's number, is your teacher a satanist?
Wiki User
∙ 13y ago
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