A 5.0kg box is pushed across the floor with a force of 32N What is the frictional force on the box if the boxs acceleration is 3.6mS2?

Answer 1

Frictional force equals 14 Newtons

Fnet = Fp - Ff so rewriting the equation gives us: Ff = Fp - Fnet

(Fnet is net force, Fp is force of push, and Ff is frictional force)

We already know that Fp is 32 N and we can find Fnet by using Newton's Second Law: F = ma

Fnet equals 5 kg times 3.6 m/s2 = 18 N

So Ff = 32 N - 18 N which equals 14 N