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A 730 N student stands in the middle of a frozen pond with a rdius of 5m to overcome the lack of friction he throws a 2.6 kg book at 5ms how long does it take for him to reach the other side?
Wiki User
∙ 12y ago
I'm going to assume that he throws the book horizontally. Please hold your
applause until the calculations are complete and the answer is stated.
-- The student gives the book [ mv = 2.6 x 5 = 13 kg-m/sec ] of horizontal momentum
that way, thus giving himself 13 kg-m/sec of horizontal momentum the other way.
-- His own mass is 750/9.8 kg. His momentum is mv = 13 = 750v/9.8
His 'v' is 13 x 9.8/750 meters per second.
-- He has 5 meters to go to reach the coast/shore. The time it will take him
to slide that far is
T = (distance)/(speed) = 5/v = 5 x 750/(13 x 9.8) = 29.435 seconds (rounded)
Thank you. Thank you.
Wiki User
∙ 12y ago
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