Assume the table were frictionless, then Tension according to formula is given by":
T=m1m2g/(m1+m2) ,so
T= 9*5*9.8/(9+5) = 31.5N.
But now presence of friction will reduce it. So
Friction acting on mass on table= 0.2* its weight= 0.2*5*9.8=10N , so net tension in the string is T=31.5N-10 N=21.5N. and that is it!
coefficient kinetic
The FORCE of Friction is INDEPENDENT of Surface Area. Only the 'Coefficient of Friction', and the Force between the two Surfaces. Sliding Friction is greater than Rolling Friction ONLY if the Coefficient of Friction is GREATER for the Sliding Surfaces.
Coefficient of rolling friction will always be less than that of sliding friction. Hence more force is required to overcome sliding friction. Because the force = coefficient of friction x normal force (ie weight of the body)
higher
higher
higher
The normal force between the two objects and the coefficient of friction. Force of friction = normal force x coefficient of friction.
Sliding friction is always less than the static friction by small amount.
static friction is higher in most cases, if you're talking about the coefficient of static or kinetic friction
The larger the value of μ (aka Mu, the coefficient of friction, the greater the frictional force on an object. For instance, steel on nonlubricated steel has a μ of 0.58 while steel on lubricated steel has a μ of 0.06.
Just multiply the weight by each coefficient, add them together and multiply by 9.8
The inverse of it's sliding friction coefficient. It's slippery-ness.