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Assume the table were frictionless, then Tension according to formula is given by":

T=m1m2g/(m1+m2) ,so

T= 9*5*9.8/(9+5) = 31.5N.

But now presence of friction will reduce it. So

Friction acting on mass on table= 0.2* its weight= 0.2*5*9.8=10N , so net tension in the string is T=31.5N-10 N=21.5N. and that is it!

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Q: A 9.0 kg hanging weight is connected by a string over a pulley to a 5.0 kg block sliding on a flat table If the coefficient of the sliding friction is 0.20 what is the tension in the string?
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