/*We can calculate this with a lot of methods
I'll explain only one of them */
*str = "abcd"; // this is a input string
printf("%d", strlen(str));
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
In python, type the following into a document. NOTE: Sentences following a # symbol are comments, and are not necessary for the program to run. #!/usr/bin/python #This program takes a input from a user and reverses it. number = input("Type a number: ") #This takes input from a user. a = len(number) #This finds the length of the number reverse = "" #This sets the variable reverse to an empty string. for i in number: a = a-1 #The places in a string start from 0. The last value will be the length minus 1.reverse = reverse + number[a] #Makes the number's last digit the new string's first. print("The reverse of", number, "is", reverse + ".") #prints the resulting string. This program will take any sequence of characters and reverse them. The final value is a string, but if an integer is needed, one needs only to add the line reverse = int(reverse) above the print statement. However, this will stop the program from being able to reverse strings, as it is not possible to convert a string to an integer if it is not a number.
CLS PRINT "PROGRAM: Print squares of all even numbers from 1 to 20" PRINT PRINT "number", "squared" PRINT FOR number% = 1 TO 20 IF number% MOD 2 = 0 THEN PRINT number%, number% * number% END IF NEXT END
To print lucky numbers in java, you must give the following program: class example { static public void main(String[] args) { System.out.println("Lucky number is your favourite number which is your DOB"); } }
first sort the ten numbers in descending order and print the first number. That will be the largest no
Use for loop declare string array str[] and string variable l= string length of string array j=l for i=0 to i=l/2 then temp=str[i] str[i]=str[j-1] str[j-1]=temp j=j-1 now print str array it will be reversed
Inversing of a given Number. suppose we gave input 123456 then the output of the program will be 654321./*mycfiles.wordpress.comC program to print inverse of a given number*/#include#includevoid main(){long int n,rn=0,d=0;clrscr();printf("Enter the number\n\n");scanf("%ld",&n);while(n>0){d=n%10;rn=rn*10+d;n=n/10;}printf("%ld",rn);getch();}
print c co com comp compu
Let's say your string is a variable called "string" To print out all the characters in order, you would do: for i in string: print(string[i]) If you wanted to print out characters up to a point (n = maximum characters): for i in range(n): print(string[i]) hope this helps!
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Here's a Python program that accomplishes this: def convert_case(input_str): return input_str.swapcase() user_input = input("Enter a string: ") converted_str = convert_case(user_input) print("Converted string:", converted_str)
If you forget the semicolon, your program won't compile.