All the time the ball is in the air, its acceleration is 9.8 meters (32.2 feet) per second2 downward. In other words ...
Every second it's in the air, its downward speed is that much faster than it was one second earlier.
When it reaches its highest point, its speed will be zero.
Two seconds earlier, its DOWNWARD speed was that much LESS than it is at the top. In other words ...
Its UPWARD speed was that much MORE than it is now.
So 2 seconds ago, its upward speed was (2 x 9.8) = 19.6 meters per second / (2 x 32.2) = 64.4 feet per second.
A the highest point its velocity will be zero.
51 seconds.
The Answer Is: 4 feet per second.
40.81632653 or (rounded to the nearest 10th) 40.8 seconds
"8 seconds" is not a velocity.
A the highest point its velocity will be zero.
You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 3 seconds?
it is 10 meters per second straight down
51 seconds.
The Answer Is: 4 feet per second.
Assuming that you travel 882 feet in a straight line, the average velocity is 882.5 = 176.4 feet per second.
Acceleration is the time rate of change of velocity. If velocity is constant, then acceleration is zero. Note: "100 km per h for 10 seconds" is a constant speed, but not necessarily a constant velocity, since we're told nothing about the direction. If the car moves in a perfectly straight line during those 10 seconds, then its velocity is constant. If it makes a curve, then its velocity is not constant even though its speed is, and there is acceleration.
v = vo + gt = 2(m/s) + 9.8(m/s2) x 5s = 51(m/s)
40.81632653 or (rounded to the nearest 10th) 40.8 seconds
Velocity increases after 5 seconds
Velocity is derived by dividing displacement with time in seconds
The velocity = (location at 40 seconds - location at 20 seconds)/20 in the direction in which the object is moving.