All the time the ball is in the air, its acceleration is 9.8 meters (32.2 feet) per second2 downward. In other words ...
Every second it's in the air, its downward speed is that much faster than it was one second earlier.
When it reaches its highest point, its speed will be zero.
Two seconds earlier, its DOWNWARD speed was that much LESS than it is at the top. In other words ...
Its UPWARD speed was that much MORE than it is now.
So 2 seconds ago, its upward speed was (2 x 9.8) = 19.6 meters per second / (2 x 32.2) = 64.4 feet per second.
The velocity of the ball at its highest point is 0 m/s. At the highest point of its trajectory, the ball's vertical velocity slows to 0 before changing direction and starting to fall back down due to the force of gravity.
No, the motion of the seconds hand of a watch is not an example of uniform velocity. The seconds hand moves in a circular motion at a constant speed, rather than moving in a straight line at a constant velocity. Uniform velocity refers to motion in a straight line with a constant speed.
The velocity of the ball will be -30 m/s (downward) after 5 seconds due to gravity.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 3 seconds?
The velocity of the ball at its highest point is 0 m/s. At the highest point of its trajectory, the ball's vertical velocity slows to 0 before changing direction and starting to fall back down due to the force of gravity.
No, the motion of the seconds hand of a watch is not an example of uniform velocity. The seconds hand moves in a circular motion at a constant speed, rather than moving in a straight line at a constant velocity. Uniform velocity refers to motion in a straight line with a constant speed.
The velocity of the ball will be -30 m/s (downward) after 5 seconds due to gravity.
it is 10 meters per second straight down
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
The magnitude of the velocity would reach 72 km/hr at around 5 seconds based on the graph shown. This is when the slope of the velocity-time graph is steepest, indicating the highest rate of change in velocity.
When a body is thrown upwards, it reaches its highest point where its velocity momentarily becomes zero before descending due to the gravitational force pulling it back down. This momentary stop at the highest point is due to the balance between the upward velocity from the initial throw and the downward pull of gravity.
The arrow will begin to fall when its velocity becomes negative, which will happen after it reaches its maximum height and starts to descend. The time it takes for the arrow to reach its peak height can be calculated using the formula: time = (final velocity - initial velocity) / acceleration. After reaching the peak, the arrow will take the same amount of time to fall back down.
Assuming that you travel 882 feet in a straight line, the average velocity is 882.5 = 176.4 feet per second.
Since the bullet is fired straight upward, it will be decelerating due to gravity acting in the opposite direction of its initial velocity. Thus, at t = 3 seconds, the velocity will be less than 36ft per second but still positive (as it's moving upward). To calculate the exact velocity, you would need to use the kinematic equation for velocity in one dimension.