answersLogoWhite

0

All the time the ball is in the air, its acceleration is 9.8 meters (32.2 feet) per second2 downward. In other words ...
Every second it's in the air, its downward speed is that much faster than it was one second earlier.

When it reaches its highest point, its speed will be zero.

Two seconds earlier, its DOWNWARD speed was that much LESS than it is at the top. In other words ...

Its UPWARD speed was that much MORE than it is now.

So 2 seconds ago, its upward speed was (2 x 9.8) = 19.6 meters per second / (2 x 32.2) = 64.4 feet per second.

User Avatar

Wiki User

15y ago

What else can I help you with?

Continue Learning about Physics

A ball is thrown with enough speed straight up so that it is in the air several seconds What is the velocity of the ball when it gets to its highest point?

The velocity of the ball at its highest point is 0 m/s. At the highest point of its trajectory, the ball's vertical velocity slows to 0 before changing direction and starting to fall back down due to the force of gravity.


Does motion of seconds hand of a watch represent uniform velocity?

No, the motion of the seconds hand of a watch is not an example of uniform velocity. The seconds hand moves in a circular motion at a constant speed, rather than moving in a straight line at a constant velocity. Uniform velocity refers to motion in a straight line with a constant speed.


You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 5 seconds?

The velocity of the ball will be -30 m/s (downward) after 5 seconds due to gravity.


What is tje velocity of a ball thrown upward at 16 ft/sec?

If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.


A rock is dropped from a height of 60 m and is in free fall. What is the velocity of the rock as it reaches the ground 3.5 seconds later?

The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.

Related Questions

You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 3 seconds?

You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 3 seconds?


A ball is thrown with enough speed straight up so that it is in the air several seconds What is the velocity of the ball when it gets to its highest point?

The velocity of the ball at its highest point is 0 m/s. At the highest point of its trajectory, the ball's vertical velocity slows to 0 before changing direction and starting to fall back down due to the force of gravity.


Does motion of seconds hand of a watch represent uniform velocity?

No, the motion of the seconds hand of a watch is not an example of uniform velocity. The seconds hand moves in a circular motion at a constant speed, rather than moving in a straight line at a constant velocity. Uniform velocity refers to motion in a straight line with a constant speed.


You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 5 seconds?

The velocity of the ball will be -30 m/s (downward) after 5 seconds due to gravity.


You throw a ball straight up with a velocity of 40 meters per second What is the ball's velocity after 5 seconds?

it is 10 meters per second straight down


What is tje velocity of a ball thrown upward at 16 ft/sec?

If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.


A rock is dropped from a height of 60 m and is in free fall. What is the velocity of the rock as it reaches the ground 3.5 seconds later?

The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.


Use the following graph of a car traveling on a straight northerly path to answer this question. At what time would the magnitude of the velocity reach 72 kmhr?

The magnitude of the velocity would reach 72 km/hr at around 5 seconds based on the graph shown. This is when the slope of the velocity-time graph is steepest, indicating the highest rate of change in velocity.


What makes a thrown upwards body to stop for some few seconds before desendeing down?

When a body is thrown upwards, it reaches its highest point where its velocity momentarily becomes zero before descending due to the gravitational force pulling it back down. This momentary stop at the highest point is due to the balance between the upward velocity from the initial throw and the downward pull of gravity.


An arrow is shot straight up at an initial velocity of 200 meters per seconds. How long will it be before beginning to fall?

The arrow will begin to fall when its velocity becomes negative, which will happen after it reaches its maximum height and starts to descend. The time it takes for the arrow to reach its peak height can be calculated using the formula: time = (final velocity - initial velocity) / acceleration. After reaching the peak, the arrow will take the same amount of time to fall back down.


What is the velocity if you travel 882 ft in 5 seconds?

Assuming that you travel 882 feet in a straight line, the average velocity is 882.5 = 176.4 feet per second.


If a gun is fired straight upward and the bullet leaves the gun at 100ft per second after 2 seconds the velocity of the bullet is 36 feet per second what is the velocity after 3 seconds?

Since the bullet is fired straight upward, it will be decelerating due to gravity acting in the opposite direction of its initial velocity. Thus, at t = 3 seconds, the velocity will be less than 36ft per second but still positive (as it's moving upward). To calculate the exact velocity, you would need to use the kinematic equation for velocity in one dimension.