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A ball thrown up vertically returns to the thrower after 6 seconds find the velocity with which it was thrown up?
Wiki User
∙ 8y ago
The velocity changes from [ V upward ] to [ V downward ].
The total change in velocity is [ 2V ].
Acceleration = (change in velocity) divided by (time for the change) = 2V/6
But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .
9.8 = 2V / 6
2V = 58.8
V = 29.4 meters per second upward
Wiki User
∙ 14y ago
Wiki User
∙ 8y agoi need the deceleration....
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In throwing a ball upward discuss the velocity and acceleration when the ball returns to the thrower's hand?
A the moment when the ball just touches the thrower's hand, it will have the velocity with which it was thrown and the acceleration will be equal to the acceleration due to gravity at the place acting vertically downwards.
What is displacement if a ball is thrown up with certain velocity it attains maximum height and comes back to the thrower?
Zero
What is the magnitude of its velocity after falling 11.0 rm m?
I believe this is the original question: A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 6.10 . Air resistance may be ignored, so the water balloon is in free fall after it leaves the thrower's hand. What is the magnitude of its velocity after falling a distance 11.0 ? (Vf)^2 = (Vi)^2 +2a( f- i) ( f- i)= 11m (Vf)^2 =(6.1)^2 +2*9.8(11) (Vf)^2 =252.81 Vf=15.9
Why does a projectile move upwards when thrown upwards even though a force of gravity acts downwards on it?
In the act of "throwing", the thrower imparts an upward velocity to the object, by temporarily applying an upward force to it that's greater than the downward force of gravity. During that brief period, the sum of the forces on the object is directed upward, so it accelerates in that direction. After the throwing ends, however, the only force on the object is the force of gravity, directed downward, so its acceleration is downward. That means that the upward velocity becomes smaller and smaller, until it's zero at the peak of the arc, and the velocity then becomes downward as the object begins to fall from its peak..
If a person in a train moving at high speeds threw a ball straight into the air would the ball continue at the same speed as the thrower or would it travel a different speed?
Assuming the train continues moving at constant speed, the ball would travel at the same speed as the thrower.
In throwing a ball upward discuss the velocity and acceleration when the ball returns to the thrower's hand?
A the moment when the ball just touches the thrower's hand, it will have the velocity with which it was thrown and the acceleration will be equal to the acceleration due to gravity at the place acting vertically downwards.
The velocity of a baseball 4 seconds after it is thrown vertically upward with a speed of 32.1 is?
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What is the name of the Australian throwing stick that returns to its thrower?
Boomerang
What is the name of the Australian throwing stick that returns to the thrower?
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What is an Aztec spear thrower called?
An Aztec spear thrower is called an atlatl. It is a tool used to increase the velocity and distance of a thrown spear by providing leverage for the thrower.
What is a booomerang?
A flat, curved, usually wooden missile configured so that when hurled it returns to the thrower.
What is stalling in ultimate frisbee?
Stalling is when the thrower takes more than ten seconds to throw the disc. The marker (defender on disc) is counting and if the thrower does not throw it in ten seconds, then it is a turnover. It is a way to speed up the game.
What is displacement if a ball is thrown up with certain velocity it attains maximum height and comes back to the thrower?
Zero
What is the magnitude of its velocity after falling 11.0 rm m?
I believe this is the original question: A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 6.10 . Air resistance may be ignored, so the water balloon is in free fall after it leaves the thrower's hand. What is the magnitude of its velocity after falling a distance 11.0 ? (Vf)^2 = (Vi)^2 +2a( f- i) ( f- i)= 11m (Vf)^2 =(6.1)^2 +2*9.8(11) (Vf)^2 =252.81 Vf=15.9
A ball is thrown vertically upward it returns back in the hand of the thrower in 60 seconds how high does it go?
Assuming the ball is thrown in a constant gravitational field causing an acceleration of 9.81 m/s/s (similar to Earth's surface), y(t) = H + Vt - (g/2)(t^2) Where H is its original height above your chosen origin, V is its initial upward velocity, g is the acceleration due to gravity (9.81 m/s/s) and t is the number of seconds after throwing it. If we set H to 0 (arbitrarily making the ball's initial height 0) and if are interested in a path wherein the ball takes 60 seconds to return to its original height (0), we say: y(60) = 0 + V(60) - (g/2)(60^2) The problem states that it "returns back to the hand" at 60 seconds. This implies that at 60 seconds, it is back at its original position (y(60) = 0) therefore: y(60) = 0 = 0 + V(60) - (g/2)(60^2) We can simplify the expression on the RHS above to find V. The equation for projectile motion is parabolic with respect to time - this means that, by symmetry, the greatest height is achieved at half the time it takes to return. Plug 30 seconds into the above equation, and I get a result of 4414.5 m. That's almost three miles high!
What is the birth name of Albert Thrower?
Albert Thrower's birth name is Albert Dabney Crenshaw Thrower.
How tall is Mitch Thrower?
Mitch Thrower is 6'.
