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F = m A

where . . .

F = force acting on the mass
m = mass of the mass
A = acceleration of the mass


F = (2.5) x (6.0)

= 15 kg-m/sec2 = 15 newtons

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14y ago
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11y ago

According to the definition of acceleration, that is the variable quantity of velocity in unit time, a=(vt-v0)/t, we can know the acceleration of this object is 4m/s2.

On the basis of Newton's second law, that is The net force acting on a object is equal to the product of mass and acceleration of an object.

F=m*a, where F is the net force acting on an object, m is the mass of an object, a is the acceleration of an object.

On the grounds of formula, we can calculate that the net force acting on a 6kg object is 24N.

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9y ago

The force acting on the object is 100 newtons.

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6y ago

Just use Newton's Second Law: F=ma (force = mass x acceleration). The units for the answer, in this case, will be newton.

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6y ago

force = mass x acceleration = 5 x 6 = 30kgm/s/s = 30 Newtons

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9y ago

300 newtons.

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6y ago

F = ma = 2 x 5 = 10 Newtons

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6y ago

The force required is 10 Newtons.

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9y ago

30N

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6y ago

45n

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Q: What net force is necessary to give a 2.0 kg mass initially at rest an acceleration of 5.0 ms2?
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