F = m A
where . . .
F = force acting on the mass
m = mass of the mass
A = acceleration of the mass
F = (2.5) x (6.0)
= 15 kg-m/sec2 = 15 newtons
According to the definition of acceleration, that is the variable quantity of velocity in unit time, a=(vt-v0)/t, we can know the acceleration of this object is 4m/s2.
On the basis of Newton's second law, that is The net force acting on a object is equal to the product of mass and acceleration of an object.
F=m*a, where F is the net force acting on an object, m is the mass of an object, a is the acceleration of an object.
On the grounds of formula, we can calculate that the net force acting on a 6kg object is 24N.
The force acting on the object is 100 newtons.
Just use Newton's Second Law: F=ma (force = mass x acceleration). The units for the answer, in this case, will be newton.
force = mass x acceleration = 5 x 6 = 30kgm/s/s = 30 Newtons
300 newtons.
F = ma = 2 x 5 = 10 Newtons
The force required is 10 Newtons.
30N
45n
If a force of 30 N imparts an acceleration of 5 to an object and we desire only one fifth of that acceleration, then we apply only one fifth of that force. Take the 30 N and divide it by 5 and we find that 6 N is the force required to give our test object an acceleration of 1.
49N
The force required is 50 newtons or 5.1kgf.
unbalanced forces cause acceleration, an object in freefall has gravity as an unbalanced force.
Force equals mass times acceleration. To change a speed, you must apply some force (either positive or negative) to give the object some acceleration. How quickly the object's speed changes will correspond to the force given divided by the mass of the object. (ie, the acceleration)
You ignore the acceleration, and just give them the mass. Now, if they give you the acceleration and the applied force, you could use m = F/a.
If a force of 30 N imparts an acceleration of 5 to an object and we desire only one fifth of that acceleration, then we apply only one fifth of that force. Take the 30 N and divide it by 5 and we find that 6 N is the force required to give our test object an acceleration of 1.
Acceleration is 0.25m/s2 (A = force/mass).
There is some confusion here. 500 newtons IS a force. You don't "give a force an acceleration". You can accelerate an object (which has a mass), but not a force.
Balance the force on all direction and after all cancellation, the remain force give the direction the object go. For matter of speed and acceleration, check it mass and find out the acceleration from force.
Greater acceleration, F=ma.
work,velocity,force and acceleration
Just use Newton's Second Law: force = mass x acceleration. In this case, solve for acceleration.
You do not need force. Velocity is the integral of acceleration with respect to time. The orthogonal components of acceleration can be integrated independently to give the orthogonal components of velocity.
If you are finding force, you most likely already know the mass and acceleration of an object. Multiply the mass by the acceleration to find the force (units of force is newtons).
49N
No it is not because its direction is constantly changing. It is not a constant force. Force has direction as well as magintude and while it magnitude is constant its direction is not.