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Use Pythagoras' theorem to calculate the magnitude of the velocity (the speed):

Sqrt(10^2 + 5^2) = sqrt(125) = 11.2 km/h

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Q: A boat heading north crosses a wide river with a speed of 10kmhr relative to water the river has a speed of 5kmhr due east what is the velocity of the boat w respect to a stationary ground observer?
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