The body will continue to rise until the force of gravity acting against its motion brings it to a stop before it falls back down to its starting position due to gravity pulling it back down. The total time of flight and maximum height reached depend on the initial velocity of the body and the acceleration due to gravity.
The displacement of the body would be zero since it returns to its starting position after reaching the maximum height. Displacement is a vector quantity that represents the change in position of an object from its initial to final location. In this case, the body ends up where it started, so the displacement is zero.
At the highest point, the velocity of an object thrown vertically into the air is momentarily zero as it changes direction. This is the point where it transitions from going upward to downward.
The speed decreases when an object is thrown vertically up because of the force of gravity acting against the object's upward motion. As the object goes higher, the force of gravity slows it down until the object reaches its maximum height, where its speed momentarily becomes zero before accelerating back downward.
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.
The displacement of the body would be zero since it returns to its starting position after reaching the maximum height. Displacement is a vector quantity that represents the change in position of an object from its initial to final location. In this case, the body ends up where it started, so the displacement is zero.
At the highest point, the velocity of an object thrown vertically into the air is momentarily zero as it changes direction. This is the point where it transitions from going upward to downward.
An object thrown vertically up wards from the ground returned back to the ground in 6s after it was thown up if it reached a height of 12m calculate?
The speed decreases when an object is thrown vertically up because of the force of gravity acting against the object's upward motion. As the object goes higher, the force of gravity slows it down until the object reaches its maximum height, where its speed momentarily becomes zero before accelerating back downward.
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?
Height reached = 3.7 metres.The mass of the ball is not really relevant.
It depends on the height of the building and also on the direction the object is thrown in (up, down etc.).
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.
The answer depends on whether the ball is thrown vertically upwards or downwards. That critical piece of information is not provided!
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
It is converted to the ball's velocity or it is known as its velocity because displacement changes with time is known as velocity.
They might seem like they have the same flight patterns, but they don't. A 12-6 curveball thrown by an over-hander will go from 12 to 6, but if the same is thrown by a 3/4 or side-armer, the ball will react a little more like a slider.