Wiki User
∙ 14y agoIt is converted to the ball's velocity or it is known as its velocity because displacement changes with time is known as velocity.
Wiki User
∙ 14y agoThe displacement of a vertically thrown ball changes according to the laws of projectile motion. Initially, the displacement increases as the ball rises, reaching a maximum height, then decreases as the ball falls back down. The displacement-time relationship is parabolic, with the ball returning to its initial position after completing one full cycle.
Wiki User
∙ 13y agoIn that case, the velocity will continuously decrease, and eventually become negative.
It is converted to the ball's velocity or it is known as its velocity because displacement changes with time is known as velocity.
The ball is affected by the force of the earth's gravity.
The maximum displacement of the ball can be calculated using the equation: [ \text{Displacement} = \frac{{\text{Initial velocity}^2}}{2 \times \text{Acceleration}} ] Assuming the ball is thrown vertically and ignoring air resistance, we can use an acceleration of -9.8 m/s^2 to represent the acceleration due to gravity. So, the maximum displacement of the ball would be 0.82 meters.
The displacement of the ball from when it was thrown to when it returns to the thrower is zero, as the ball has completed a full round trip back to its initial position. Displacement is a vector quantity that measures the change in position from the initial point to the final point.
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.
It is converted to the ball's velocity or it is known as its velocity because displacement changes with time is known as velocity.
The ball is affected by the force of the earth's gravity.
The ball is affected by the force of the earth's gravity.
The ball is affected by the force of the earth's gravity.
The answer depends on whether the ball is thrown vertically upwards or downwards. That critical piece of information is not provided!
The maximum displacement of the ball can be calculated using the equation: [ \text{Displacement} = \frac{{\text{Initial velocity}^2}}{2 \times \text{Acceleration}} ] Assuming the ball is thrown vertically and ignoring air resistance, we can use an acceleration of -9.8 m/s^2 to represent the acceleration due to gravity. So, the maximum displacement of the ball would be 0.82 meters.
The displacement of the ball from when it was thrown to when it returns to the thrower is zero, as the ball has completed a full round trip back to its initial position. Displacement is a vector quantity that measures the change in position from the initial point to the final point.
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.
At the highest point of its trajectory, a ball thrown vertically upwards has zero velocity. Since momentum is the product of velocity and mass, the momentum of the ball at the highest point is also zero.
if the bal is thrown by making 45 degree angles. with the ground..it will travel maximum distance...
They might seem like they have the same flight patterns, but they don't. A 12-6 curveball thrown by an over-hander will go from 12 to 6, but if the same is thrown by a 3/4 or side-armer, the ball will react a little more like a slider.
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?