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Perhaps you meant speed or velocity, because the vertical acceleration is constant throughout the bomb's decent, ignoring the effects of air resistance. The acceleration due to gravity is 9.8 m/s2 for all values of t.

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Q: A bomber jet releases its bomb from a height of 4000 meters What is the acceleration of the bomb after 5 seconds?
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David drops a ball from a bridge at an initial height of 70 meters what is the height of the ball to the nearest tenth of a meter exactly 2 seconds after he releases the ball?

Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters


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The effect of increasing the height of the track on the acceleration of the object is that more work is required to accelerate. It increases the gravity.


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