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Q: A brick is thrown vertically upward with an initial speed of 2.60 meter per sec from the roof of a building If the building is 100.0 m tall how much time passes before the brick lands on the ground?

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It would be 9.81 m/s^2. Sahil Afghan

this is because when the area of contact between the ground and the building increases the pressure exerted by the building will be less for the same force.

-- the gravitational attraction between the football and the Earth, acting vertically downward; -- the normal force of the ground or the shelf under the football, acting vertically upward. These two forces are precisely equal and opposite. If they're weren't, then the football would be accelerating vertically, not at rest.

That depends on the mass of the lead weight and the time it took to cover the rest of the fall.

Potential energy depends upon the datum(initial condition ) chosen.If we take ground as datum potential energy is zero

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Vertically, about 300 meters,

By the Way, guys, this is based on the equation H= -16t2+vt+s

An object thrown vertically up wards from the ground returned back to the ground in 6s after it was thown up if it reached a height of 12m calculate?

The height of the building is 57.3 meters.

Some very wise man noticed that the shadow cast from a stick placed vertically in the ground was a different angle at exactly noon than the angle of shadow cast at exactly noon from a vertically placed stick in the ground at a location further north. By employing mathematics, he was able to deduce that the earth is in fact, roundish.

-- the initial horizontal speed of the projectile -- the time it remains in flight before it hits the ground

The building is h=.5 gt^2 meters tall; that is = .5x9.8 x25 =122.5 meters.