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A bullet of mass 10 grams moving with a velocity of 400 m s gets embedded in a freely suspended wooden block of mass 900 grams what is the velocity acquired by the block?
DigvijayHadafb9094
The answer is: The momentum (mv) after the collision is the same as
the momentum before it. The rest is just arithmetic.
Before the collision, the momentum of the bullet is mv=(0.01)x(400) = 4 kg-m/sec.
After the collision, the combined mass of the wood block plus the bullet is 910 gm.
Its momentum mv=(0.910)x(v) = 4 kgm-m/sec.
v = 4/0.910 = 4.396 m/sec .
I've ignored the momentum lost during the embedding due to crunching and splintering,
both because I don't know anything about the properties of the wood, and also because
I wouldn't know what to do with them.
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