A bus is beginning to move with an acceleration of 1 meter per sec a man who is 48 m behind the bus starts running at 10 meter per sec After what time will he be able to catch the bus?

Answer 1

To answer this ,let us suppose that the man catch the bus in 't' sec.

Then the distance travelled by the man = (10 x t) meters

and that travelled by bus = (10t - 48) meters

Now,S = ut + 1/2 at2

(10t - 48) = 0 x t + 1/2x 1 x t2

or t2 - 20t + 96 = 0

or t2 - 12t - 8t + 96 = 0

or t(t - 12) - 8(t-12) = 0

or (t- 8) (t-12) = 0

Therefore, t = 8 seconds or t = 12 seconds

The man will catch the bus after 8 seconds..

Answer 2

To find the time it takes for the man to catch the bus, we need to determine when the distance between them is zero. We can use the equation: distance_man = distance_bus + velocity_bus * time + 0.5 * acceleration_bus * time^2. Solving for time gives us approximately 12 seconds.