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A bus is beginning to move with an acceleration of 1 meter per sec a man who is 48 m behind the bus starts running at 10 meter per sec After what time will he be able to catch the bus?
Wiki User
∙ 13y ago
To answer this ,let us suppose that the man catch the bus in 't' sec.
Then the distance travelled by the man = (10 x t) meters
and that travelled by bus = (10t - 48) meters
Now,S = ut + 1/2 at2
(10t - 48) = 0 x t + 1/2x 1 x t2
or t2 - 20t + 96 = 0
or t2 - 12t - 8t + 96 = 0
or t(t - 12) - 8(t-12) = 0
or (t- 8) (t-12) = 0
Therefore, t = 8 seconds or t = 12 seconds
The man will catch the bus after 8 seconds..
Wiki User
∙ 13y ago
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