m = mass of car
dV = change of velocity
dM = change in momentum
T= time
a = acceleration mile/hour2
dVmph =40mph - 30mph
dVmpg = a*T
dM = mdV*T
F = ma
impulse = FT = maT
1000000
It is an example of a velocity.
30mph
0.8 kilometres/Min ~ 48km/hr ~ 30mph
The kinetic energy of the vehicle when it is travelling faster is four times as great. It the brakes apply the same retardation and the friction from the tires on the road surface is unchanged then the stopping time will be four times as long.
30mph
Yes and No. No in the sense that the speed is not changing. What you are feeling is the change in direction as the car rounds the turn, an effect called centripetal acceleration.
30mph
30mph
30mph
Missing data. That would depend on the acceleration, and that depends on the condition of the brakes, the condition of the road, and other factors. Or even if it was driven into a concrete barrier, in which case time = 0 (nearly).
48.28032 kph ==
i think 30mph
around 30mph
they can run 30mph
30mph
75 Feet