Acceleration = (change in speed) / (time for the change)
3 = (30) / (time)
3 x (time) = 30
time = 30/3 = 10 seconds
IF your question accelerates towards me at 6megabytes per second then how long will it take me to answer(deccelerate) it if my current velocity is 299.996 miles per second.
I am assuming the initial speed is 6.2 m/s Let upward motion be positive! Gravity decreases the speed by 9.8 m/s each second Acceleration due to gravity = -9.8 m/s each second (negative because gravity accelerates objects downward) Find time to reach the top of the path! Final velocity at the top = 0 m/s Initial velocity = 6.2 m/s Final velocity = Initial velocity + acceleration * time Time - = (final velocity - initial velocity) ÷ acceleration Time = (0 - 6.2) ÷ -9.8 = 0.633 seconds (to reach top) The path is symmetrical. 0.633 seconds to reach top and 0.633 seconds to reach glove again. Total time = 12.66 seconds
Speed=15t + 10 The 15t accounts for acceleration, while the initial velocity of 10 is accounted for by +10. As such, the amount of time (t) for the car to reach 20m/s is 2/3s.
How long will depend on the velocity. The closest star would be 4.24 light years away
From my knoledge only a few seconds - minutes because of the high velocity heading down on earth
It accelerates as long as the force is applied, and after that it continues at a uniform speed and direction.
Yes. Not just a skydiver; anything that falls long enough will eventually reach "terminal velocity", which means that it will continue falling at a constant speed, because the force of gravity and the force of air resistance are in balance.
radius and rpm is not enough you need to know changes in speed over time, so you need to measure how long it takes from "0" velocity to reach maximum velocity
Using the equation v = u + at, where v is the final velocity, u is the initial velocity (0 m/s in this case), a is the acceleration (9.8 m/s^2), and t is the time taken, we can rearrange the equation to solve for time: 22.8 = 0 + 9.8t. Solving for t gives t = 22.8 / 9.8 ≈ 2.33 seconds.
No. It means how far you went AND how long it took to get there. Velocity = displacement (how far and which direction) / time (how long it took to get there)
A larger parachute will experience greater air resistance, slowing down its fall and increasing the time taken to reach the ground. Conversely, a smaller parachute will experience less air resistance, resulting in a quicker descent and less time to reach the ground.
It accelerates as long as the force is applied, and after that it continues at a uniform speed and direction.