To solve this problem, I must explain the concept of vectors. Vectors merely consist of a magnitude and a direction. For this type of problem, the magnitude is the distance the car travels. Imagine arrows that are pointed in the direction of movement, and the same distance as the car moves. In this case, we will say that north is zero degrees. We know that since the car travels 215 km west, the first displacement is 215 west, and this is easy to visualize exactly where the car is. However, since the 85 km displacement is diagonal, it is more difficult to determine where exactly the vector goes. We must break this into components, in other words, two separate vectors. We must find out how far the car moves in the north-south direction, and how far it moves in an east-west direction. We do this using trigonometry. When we assumed that north is zero degrees, we determine that southwest corresponds to -135 degrees. So the calculations go as follows. For the east-west component, 85cos(-135)=-60.104 km. This means that the displacement from this vector is 60.104 km west. For the north-south component, 85sin(-135)= -60.104 km. This means that the displacement for this vector is 60.104 km south. We then add these two vectors to the 215km west. 215km + 60.104km = 275.104km. This means that the car has traveled a total of 275.104 km west. Since the car didn't travel south initally, we can just say that the car traveled 60.104 km south. To find out the straightline distance that this displacement is from the start, we use the pythagreaon theorem. The west and south displacements make up the legs of a right triangle. By adding the squares of these displacements, then taking the square root of the sum, we get 281.593 km from the start point. To get the angle of this displacement, use the inverse tangent function of the north-south component divided by the east-west component. We get 12.32 degrees. We must add this to the 90 degrees we get from the west component, so in the end, the vector can be defined as 281.593 km, -102.32 degrees. Hope this helps.
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A diagram that represents the magnitude of direction's force.
A vector diagram shows direction as well as magnitude
the magnitude and direction of the vector are given.
A visual diagram representing the magnitude of a force in a direction.A vectoris an object that has both a magnitude and a direction. Geometrically, we can picture a vectoras a directed line segment, whose length is the magnitude of thevectorand with an arrow indicating the direction. The direction of the vectoris from its tail to its head
It's called a vector
No. Result= V1 + V2 = V2 + V1.
The direction of the arrow represents the direction of the force; the length of the arrow is proportional to the magnitude of the force.
One axis has the color, the other the magnitude.
'Angular displacement' is the angle by which the secondary line-to-line voltage lags the primary line-to-line voltage. It can be directly measured by constructing a phasor-diagram for the primary and secondary line-voltages for a three-phase transformer.
-0.15000000000000036
its not why its just A diagram of a compass showing direction.
its located somewhere