And what is the question?
Speed = (acceleration) x (time) = 9 x 8 = 72 ft/sec
Acceleration = (change in speed) divided by (time for the change) = (9/3) = 3 m/s2
The calculation depends on the available data. For example, if you have the corresponding information, you can subtract the final speed by the initial speed, then divide the result by the 15 seconds. This will give you the average acceleration for those 15 seconds.
At 1 m/s? It travels 5 seconds.
Just divide the speed difference by the time - a difference of 30 m/s, divided by 3 seconds, is equal to 10 m/s2.
Acceleration = (change in speed) / (time for the change)3 = (30) / (time)3 x (time) = 30time = 30/3 = 10 seconds
5 seconds
The difference in time is 10 seconds. How much slower depends on how fast you are traveling.
19.14 seconds.
there is no time limit in volleyball except for the 30 seconds allowed for timeouts and 8 seconds given to initially serve the ball.
60.912 meters in that time
1 hour 37 minutes 30 seconds.
It will take 5 seconds.
Speed = (acceleration) x (time) = 9 x 8 = 72 ft/sec
a = vf - vi/Δt, where a is acceleration, vf is final velocity, vi is initial velocity, and Δt is time interval. a = (7m/s - 1m/s)/30s = 6m/s/30s = 0.2m/s/s or 0.2m/s2
Speed= Distance / time => Distance = Speed x Time =16x8 = 128m
Average acceleration = (change in speed) / (time for the change) = (88 - 44) / (11) = 4 meters per second2