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A certain source of sound waves radiates uniformly in all directions. At a distance of 29 m from the source the intensity level is 53 db. What is the total acoustic power output of the source in watt?
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By what factor will the sound of a source change the intensity of the waves if the distance is tripled from the sound source?
For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.
How does light intensity vary with distance form the source?
Light intensity is inversely proportional to the square of the distance: I = k/d2
How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
Does sound Intensity decrease linearly with distance?
No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.
What happens to the intensity of ionizing radiation when you move away?
The intensity reduces in proportion to the square of your distance from the source.
What is the intensity level of a sounding instrument which radiates energy at the rate of 4.81W to a person standing at a distance of 15m?
If the instrument radiates energy uniformly in all directions, the sound intensity at distance of r = 15 m is:Ir = Pac / (4 pi r2) = 4.81 W / 2827 m2 = 1.7014 * 10-3 W/m2, where:Pac - acoustic power (4.81 W in this case),r - distance to listening person.Intensity level in dB is then obtained by comparing this using logarithmic scale with reference value of I0= 10-12 W/m2.L = 10 log10 (Ir / I0) = 10 * log10 (1.7014 * 10-3 / 10-12) = 10 * log10(1.7014 * 109) = 92.31 dB
What is An acoustic free field environment?
It is an environment in which there are no reflective surfaces and obstructions in all directions. In this region, the sound level drops 6dB for a doubling in distance from the sound source.
By what factor will the sound of a source change the intensity of the waves if the distance is tripled from the sound source?
For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.
An object uniformly accelerates over a distance of 100 m in 20 seconds. What is the acceleration?
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
How does light intensity vary with distance form the source?
Light intensity is inversely proportional to the square of the distance: I = k/d2
How does the intensity of a sound wave change if the distance from the source is reduced by a factor of 4?
- 6 dB is incorrect. It will decrease by 12 dB.
How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
Does sound Intensity decrease linearly with distance?
No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.
What physical law describes the manner in which the intensity of sunlight changes as the observer moves away from the sun?
The Conservation of Energy or power Law. This gives the inverse distance law of Intensity: Intensity on Earth = intensity on sun (radius/sun distance to earth)2 .
What happens to the intensity of ionizing radiation when you move away?
The intensity reduces in proportion to the square of your distance from the source.
The intensity of a sound describes?
Its loudness at a particular distance
What distance is the sound intensity level 25dB?
That depends on the sound intesity level at the point of origen. Sound fall of with the square of the distance but the original intensity must be known.
