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A dime = $0.10

A quarter = $0.25

You have received 12 coins as a mixture of dimes and quarters.

The minimum value of those 12 coins is 12 of the smaller denomination coin, ie the 12 dimes:

The sum of 12 dimes is 12 × $0.10 = $1.20

If you replace a dime by a quarter it will create a larger sum as:

you remove $0.10 but add $0.25 giving a difference of -$0.10 + $0.25 = $0.15

→ the change machine is clearly not working correctly. as the sum of the 12 coins must be at least $1.20 and you only inserted a dollar.

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However, if the machine gives change in quarters and nickels, then:

a nickel = $0.05

a quarter = $0.25

12 nickels = 12 × $0.25 = $0.60

Every time a nickel is replaced by a quarter the effect is to subtract $0.05 and add $0.25 to make an overall difference of -$0.05 + $0.25 = $0.20

→ increase the sum by $0.20

$1.00 - $0.60 = $0.40

$0.40 ÷ $0.20 = 2

→ replace 2 nickels by quarters and the total value is $1.00

→ 10 nickels + 2 quarters = 10 × $0.05 + 2 × $0.25 = $0.50 + $0.50 = $1.00

The machine gave you 10 nickels and 2 quarters.

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Q: A change machine gives change in quarters and dimes if you receive 12 coins after inserting a dollar bill how many quarters did you receive?
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