We'll consider the segments individually, list their components, then add up the components to find the resultant. Also, we'll ignore the spherical aspects of the exercise and assume that everything is taking place on a nice rectilinear Cartesian plane, plus we'll ignore the mysterious fact that we're trying to do serious math while watching a clown. Segment #1: 9.7 north. Zero east. Segment #2: 1.4 sin(20) = 1.31557 north. 1.4cos(20) = 0.47883 east. Segment #3: Zero north-south. 5.6 east. Sums: 11.01557 north. 6.07883 east. Magnitude of total displacement = sqrt( north2 + east2 ) = sqrt(121.34278 + 36.95217) = sqrt(158.29495) = 12.5815 m (rounded) Direction from north = tan-1(east/north) = tan-1(6.07883/11.01557) = tan-1(0.55184) = 28.892 degrees east of north.
6.5 m at 67 degrees north of east
The total distance traveled (corresponding to the amount of gas the car would burn on such a trip) is 26 meters.The magnitude of the displacement vector = (Dfinal - Dinitial) = 4 meters north.
nobody nos that anser
When we add up the vectors we are left with 17 paces east and 20 paces north. Tan(x) = opp/adj = 17/20 x = 40.4o - remember that this is degrees from North We can then work out the distance using trig or pythagora's theorem. I'll use pythagora's theorem: srt(20^2 + 17^2) = 26.2 paces ok, but is the direction 26.2 paces North? because you have to give magnitude and direction. The magnitude is 26.2 paces The direction is 40.4 degrees we measure degrees clockwise from north - exactly like on a compas or protractor. Thirty
You can calculate the magnitude of the displacement by using Pythagoras's Theorem. a2+b2=c2 Let a be 8, b be 6 and c be the magnitude. 8km2+6km2 = c2 64k+36km = c2 100km = c2 10km = c
80
north, 35 degrees north of east
Edward and his family are sightseeing. They walk two blocks north, four blocks west and two blocks south. All together they have walked blocks and have a total displacement magnitude only of 8. 2+4+2=8
Sarah walks part way around a swimming pool She walks 50 yards north then 20 yards east and 50 yards south. The magnitude of her total displacement during the walk is 20 yards.
The answer is 80 because 100-30+10 is 80.
No. Distance can be greater than displacement, but not less. The magnitude of the displacement between two points is also the minimum possible distance of a path between the same points.However, the displacement can be zero if the distance is not if the object's starting point and ending point are the same.
Vector quantities are quantities that have directionality as well as magnitude. Displacement (meters North) vs Distance (meters) Velocity (meters per second North) vs Speed (meters per second)