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We'll consider the segments individually, list their components, then add up the components to find the resultant. Also, we'll ignore the spherical aspects of the exercise and assume that everything is taking place on a nice rectilinear Cartesian plane, plus we'll ignore the mysterious fact that we're trying to do serious math while watching a clown. Segment #1: 9.7 north. Zero east. Segment #2: 1.4 sin(20) = 1.31557 north. 1.4cos(20) = 0.47883 east. Segment #3: Zero north-south. 5.6 east. Sums: 11.01557 north. 6.07883 east. Magnitude of total displacement = sqrt( north2 + east2 ) = sqrt(121.34278 + 36.95217) = sqrt(158.29495) = 12.5815 m (rounded) Direction from north = tan-1(east/north) = tan-1(6.07883/11.01557) = tan-1(0.55184) = 28.892 degrees east of north.

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Q: A clown runs 9.7m North turns 20 degrees East of North and runs 1.4m then the clown turns due East and runs 5.6m what is the magnitude of the clowns total displacement answer in units of m?
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