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P = 56.35 & O = 43.65 ( Total is 100 %)

Divide each by their elemental mass

P = 56.35/31 & O = 43/65 / 16

P = 1.817 & O = 2.728

Take the lowest ratio and divide into itself and into the other ratio(s).

P = 1.917/1.817 = 1

O = 2.728 / 1.817 = 1/5051...

Hence ratios are P : 1 :: O 1.5

In whole numbers. by multiplying by 2.

P = 2 :: O = 3

Hence empirical formula is P2O3

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P underscore 2 O underscore 3

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P2o3

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PCl3

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Q: A compound formed of only phosphorus and oxygen is found to be 56.35 phosphorus what is the empirical formula of the compound?
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