most reasonably it would land on 4, 1 of 6 or 16 2/3%. since it cannot land on 4 less than once the answer is 17 times of 100 throws.
mean = 5, variance = 5
The probability of a heads is 1/2. The expected value of independent events is the number of runs times the probability of the desired result. So: 100*(1/2) = 50 heads
No. When multiplying by a positive number greater than 1 the number will get bigger. 0.018 is less than 1.8 so cannot be a reasonable answer to 1.8 × 100. 1.8 × 100 = 180. 1.8 ÷ 100 = 0.018.
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once! Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25. If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.
For a regular cubic die, a reasonable point estimate is 5000.
A die has 6 sides and every side has the same probability of being chosen. So for any throw the possibility of getting a 2 is 1/6. If the die is thrown 100 times then the total number of all possible 2s would simply be (1/6)x100 or 16. To get a 2 on every throw becomes (1/6)100 or 1.5306467074865063414445284410446e-78
48
What is the question?
The number of sequences is 27 or 128.
33
Eight.
If a coin is tossed 15 times there are 215 or 32768 possible outcomes.
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
mean = 5, variance = 5
How many times storm - tossed pilgrims settle in new England
It means that if the coin were tossed an infinite number of times, half of the tosses would come up heads and half would be tails.