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Calculate the magnitude of the tension in a string by drawing a free body diagram, and then using the formula T = mg + ma.You can calculate the magnitude of the tension in a string by first drawing a Free body diagram, and then using the formula T = mg + ma.
If: A=Horizontal distance betwen ends (at same height) B=Depth of catenary C=radius of curvature at lowest point L=length along catenary M=Mass per unit length Tm=Tension at ends of catenary To=Tension at lowest point. (Also horizontal component of tension at any point) Then: C=To/M, and B=C(cosh(A/2C)-1)
Tension = mass(acceleration) + force of gravity Force of gravity equals mass times gravity (9.8m/s2)
tension is a vector!(At first I thought it was a scalar too but this afternoon it was in our physics quiz,I answered scalar but I got it wrong because tension is a vector).this is the explanation:tension is the force producing such deformation.anything with force is a vector.Force always has direction.
Putting weight on the forward pedals puts tension on the chain, which rotates the rear wheel and pushes the bike forward.
More tension causes more recoil and therefore springs the vehicle forward faster.
There is a glycerin component included that increases surface tension.
A small sphere of charge q = +68 uC and mass m = 5.8 g is attached to a light string and placed in a uniform electric field E that makes an angle O = 37 degrees with the horizontal. The opposite end of the string is attached to a wall and the sphere is in static equilibrium when the string is horizontal.(a) Find the magnitude of the electric field.(b) Find the tension in the string.
Pushing on the cranks puts tension on the chain, which rotates the rear wheel and pushes the bike forward.
engine pulls the aircraft forward but air resistance tries to hold it back results in tension which tries to stretch..............2)bracing wires are subjected to tension
front and back tension plays significance role in rolling. front tension increases the forward slip and back tension will do reverse. with increase in front tension roll force required to reduce the thickness will decrease.
the top of the arch under goes tension and horizontal thrust