At its max height 0.490m its velocity is 0
therefore we can use the equation of motion that
v^2 = u^2 + 2as
u^2 = 0 - 2 x -9.80(negavtive for direction) x 0.490
therefore u^2 = 7.644
= root 7.644
initial velocity = 2.76 m/s to 2 decimal places
hope it helps
To calculate the time you can use another equation of motion
t = (v-u)/a
substitute in :
0-2.76/-9.8
= 0.28seconds
but that's only half the journey to its maximum point therefore the time to reach back to the starting point is double this as the acceleration is the same
so the answers 0.56 seconds - im sure lol
initial velocity of the kick = 28.06 m/s
20.40
This is a velocity question so u need to use uvaxt
51 seconds.
1.6 ft
The object's initial distance above the ground The object's initial velocity
The answer will depend on what "it" is, and on what its initial velocity is.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
To answer this question one would need to know the rock's initial height and velocity.
Perhaps you mean Terminal Velocity, as in a parachute fall? This is the maximum speed reached in the fall. Final velocity will be zero, assuming you arrive on the ground.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)