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What is the approximate area of a circle with a radius of 11 m?
A circle with a radius of 11m has an area of ~380.13 m2
What is the area of a square tha measures 11 meters on one side?
121m2
What is the surface area of a piece of tile that measures 11 x 14 centimeters?
43.543
What is the area of a square that measures 11 meters on one side?
121 square meters.
What is the area of a rectangle that measures 11 feet by 7.5 feet?
82.5 ft^2
What is the area of a piece of tile that measures 11 x 14 centimeters?
154 cm2
A rectangle measures eleven centimeters by twenty centimeters What is its area?
11*20=220 cm2
What is the area for 11 and 7 and 11 and 7?
It depends on what the 4 measures given are! If they are the lengths of the sides of a parallelogram, the question cannot be answered.
What is sq ft 11x11?
To find the square footage of an area that measures 11 feet by 11 feet, you multiply the two dimensions: 11 feet × 11 feet. This calculation gives you 121 square feet. Therefore, an 11x11 area equals 121 square feet.
Use rounding and estimation to predict the approximate quotient of 285 ÷ 11?
Use rounding and estimation to predict the approximate quotient of 285 ÷ 11.
How tall is Gregory Frame?
Gregory Frame is 5' 11".
The outside of a picture frame measures 8 in by 11 in 54in2 of the picture shows find the thickness of the frame?
To find the thickness of the frame, we start by determining the dimensions of the picture itself. The area of the picture is 54 in², and since the outside dimensions of the frame are 8 in by 11 in, we can set up the equation: Let the thickness of the frame be ( x ). Then the dimensions of the picture are ( (8 - 2x) ) by ( (11 - 2x) ). Setting up the equation: [ (8 - 2x)(11 - 2x) = 54 ] Expanding and simplifying gives us: [ 88 - 22x - 16x + 4x^2 = 54 ] [ 4x^2 - 38x + 34 = 0 ] Using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ) with ( a = 4, b = -38, c = 34 ), we find ( x ). Solving this results in ( x \approx 1 ) inch. Thus, the thickness of the frame is approximately 1 inch.
