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w = -P∆V
w = -(1 atm)(0.5 L) = -0.5 L-atm
-0.5 L-atm x 101.325 J/L-atm = 50.7 J
50.7 J x 0.000239 kcal/J x 1000 cal/kcal = 12.1 calories

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Q: A gas expand by 0.5 litre against a constant pressure of one atmosphere. calculate the work done in joule and calorie.?
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