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A generator produces 100 kilo watt of power at a potential difference of 10 kilo volt The power is transmitted through cables of total resistance 5 ohmHow much power is dissipated in the cables?
Wiki User
∙ 14y ago
If the generator is delivering 100 KW of power and the Voltage is 10 KV, then it's supplying current at
I = P/E = (100,000/10,000) = 10 Amperes.
If 10A is flowing through cable with a total resistance of 5 ohms, the power dissipated by the cable is
P = I2R = (10)2 x (5) = 500 watts.
Nice problem !
Wiki User
∙ 14y ago
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