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A kangaroo jumps to a vertical height of 2.8m how long was it in the air before returning to earth?
Wiki User
∙ 14y ago
a=9.8m/s^2
delta Y=2.7m
Vf=0
Vf^2=Vi^2=2(a)(Delta Y)
0=Vi^2+2(9.8)(2.7)
Vi=7.3m/s
2.7m is just one direction so multiply it by 2 and the whole distance traveled is 5.4m
Delta Y=(Vf+Vi)/2)t
5.4=(0+7.3)/2)t
5.4=3.64t
t=1.5 seconds
Wiki User
∙ 14y ago
Wiki User
∙ 12y agoyou have to use the equation s=ut+1/2at2
where s= displacement =2.8
U= initial velocity =0
A= acceleration due to gravity =9.8
2.8=0t+1/2gt2
2.8=1/2gt2
2.8=4.9t2
2.8/4.9=t2
square root of 2.8/4.9=t
so the answer is 0.755928946 seconds
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