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A man holds a 4.0kg steel ball in hand His arm is 70cm long and has a mass of 4.0kg What is the magnitude of the torque about his shoulder if he holds his arm straight but 50 degrees below horizontal?
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A man holds a 4.0kg steel ball in hand His arm is 70cm long and has a mass of 4.0kg What is the magnitude of the torque about his shoulder if he holds his arm straight but 30 degrees below horizontal?
ball in hand = 4 * 9.807 = 39.228 nlever length = cos 30deg. * 0.7 = 0.6062 metrestorque = 39.228 * 0.6062 = 23.78 newton - metre.torque generated by arm = 23.78 / 2 = 11.89 newton - metre.total torque = 23.78 + 11.89 = 35.67 newton - metre
Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
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nobody nos that anser
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iff the angle between them is 120 degrees
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A man holds a 4.0kg steel ball in hand His arm is 70cm long and has a mass of 4.0kg What is the magnitude of the torque about his shoulder if he holds his arm straight but 30 degrees below horizontal?
ball in hand = 4 * 9.807 = 39.228 nlever length = cos 30deg. * 0.7 = 0.6062 metrestorque = 39.228 * 0.6062 = 23.78 newton - metre.torque generated by arm = 23.78 / 2 = 11.89 newton - metre.total torque = 23.78 + 11.89 = 35.67 newton - metre
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Any line that is not running exactly straight up and down is not vertical. Any line that is not running exactly flat, left to right is not horizontal. Vertical and horizontal lines are always at 90 degrees to each other.
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A graph which consists of short straight lines which keep changing direction. Example : a graph line which is inclined at say, 30 degrees to a horizontal, then changes direction instantly to a line which is say, inclined at 60 degrees to the horizontal , etc. If the shape of a graph is not a series of straight lines joined to each other, then it is not a step graph.
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Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
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Draw a straight horizontal line. Draw a 29-degree angle below the line. Indicate that 331 is the rest of the space.
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Well. Let's say you have a horizontal line (straight from one side to the other). If you had a 90 degrees angle it would go straight up, and 180 is straight to the side. Therefore 120 degrees would be something between that, a bit closer to straight up than straight to the side. I also put a link under "Related Links" below this answer.
