n = 1, 3 or 9.
No. The sum of its digits, 5 + 3 + 1, is divisible by 3, which means the number itself is also divisible by 3.
what number is prime to 40 29 - it's a prime number (divisible only by 1 and itself) and if you sum the two digits 2 + 9 = 11
If the sum of digits of a number is a multiple of 3 then it is divisible by 3. Sum of digits of 234567 = 2+3+4+5+6+7 = 27 = 3x9 So, 234567 is not a prime number because it is divisible by 3.
Answer - How do you tell if a number is divisible by 3?you add all the digits in the number and see if that number can be divided by 3 Answer - A whole number is divisible by 3 if the sum of its digits is divisible by what?Three (3) Examples:* 27 -- 2+7=9 * 13452 -- 1+3+4+5+2=15 -- 1+5=6If the sum of the digits is divisible by 3, the number is also divisible by 3. Or just do the division.
not a prime number as itβs divisible by 1, 63, 3, and 21
That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.
(The assumes that "the number" in the question is not n, although if they are they same number, this is still true.) "If the sum of the digits of the number is divisible by n, then the number itself is divisible by n" is true if n is 3 or if n is 9.
This works with 3, and with 9.
That works with 3 and 9.
A number is divisible by 3 if the sum of its digits is divisible by 3.
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.
No. The sum of its digits, 5 + 3 + 1, is divisible by 3, which means the number itself is also divisible by 3.
The sum of the digits is 27, which is divisible by 9, so the number itself is divisible by 9. When divided by 9, it equals 20307.
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