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A particular engine has a power output of 6.00 kW and an efficiency of 30.0 percent Assume the engine expels 7500 J of energy in each cycle?
Wiki User
∙ 13y ago
Output power = 6 kW = 30% of input power.
Input power = 6/0.3 = 20 kW.
Waste power = (20 - 6) = 14 kW = 14,000 joules per second.
Waste energy = 7,500 joules per engine cycle.
(14,000 joule/sec) / (7,500 joule/cycle) = 113/15 engine cycles per second
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We suspect that the question may contain a typo.
Maybe the wasted energy should be 7,000 J per cycle.
Then
(14,000 J/sec) / (7,000 J/cycle) = 2 engine cycles per second
Engine running at 1 cycle every 0.5 second.
Wiki User
∙ 13y ago
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