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Math and Arithmetic

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A stack of nickels and dimes is worth 2.55 find the number of nickels if the number of dimes is 12 less than twice the number of nickels how many nickels are there

Which 2 consecutive integers have a sum of -105

The perimeter of a square garden is 52 feet What is the length of each side

What number divided by 4 equals 6

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Q: A piggy bank contains only nickels and dimes In all there are 42 coins with a total value of 3.85 How many nickels are in the piggy bank?
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Charlie's piggy bank was filled with dimes and nickels He took the money out and counted a total of 419 coins The coins were worth 36.05 How many nickels were in the piggy bank?

117 nickles


What Manuel has some nickels and dimes in his piggy bank 26 coins altogether the number of nickels is 2 fewer than three times the number of dimes how much money does he have in his piggy bank?

He has 165 cents.


If Charlie's piggy bank was filled with dimes and nickels and he took the money out and counted a total of 419 coins which were worth 36.05 how many nickels were in the piggy bank?

117 Alternative method: If all the coins were dimes he would have $41.90; He is $5.85 short of that figure Every 5c short represents 1 nickel replacing a dime 585/5 = 117 nickels (and 302 dimes).


Lisa's piggy bank contained 21 dimes nickels and pennies The total in the piggy bank was 1.21 Lisa removed all the dimes from the piggy bank This left only 41 cents in the bank How many nickels?

7


When a piggy bank has 160 total coins valuing 10.50. Think about a system of equations that can be used to represent the number of nickels and dimes and then think through?

If n is the number of nickels and d the number of dimes, then the equations are:n + d = 160 (total number of coins) 5n + 10d = 1050 (total value). And I have thought through to the answer.


Lisa piggy bank contained 21 dimes nickels and pennies the total in the piggy bank was 1.21 Lisa removed all the dimes this left only 41 cents in the bank how many pennie were in the bank?

6 pennies


You have 1.21 dollars in your piggy bank in dimes nickel and pennys if you take out all dimes you have 41cents how many nickels do you have?

You could have: 8 nickels and 1 penny or 6 nickels and 11 pennies or 4 nickels and 21 pennies or 2 nickels and 31 pennies. The option of 0 nickels and 41 pennies is excluded by the necessity that the amount is made up of dimes, nickels and pennies; 0 nickels would mean the $1.21 was made up of dimes and pennies only.


How many coins of each type does Cameron have if he has 4.50 in nickels and dimes in his piggy bank and the number of dimes is twice the number of nickels?

In order to eliminate the decimal point, let us work with cents. So, let $ 4.50 = 450 cents. If the number of nickels is x, then the value of x nickels is 5x cents. Since the number of dimes is twice the number of nickels, then we can write the number of dimes as 2x, and the value of 2x dimes as 10(2x) or 20x cents. So we have: 5x + 20x = 450 25x = 450 divide by 25 to both sides x = 18 the number of nickels 2x = 2 x 18 2x = 36 the number of dimes Thus, Cameron has 18 nickels and 36 dimes. Check: 18 nickels = 18 x 5 cents = 90 cents or $ 0.90 36 dimes = 36 x 10 cents = 360 cents or $ 3.60 0.90 + 3.60 = 4.50? 4.50 = 4.50 True


Piggy bank contains 19.75 in dimes and quarters there are 100 coins in all how many dimes are there?

Work in cents. 10D + 25Q = 1975 and D + Q = 100 so D = 100 - Q 1000 - 10Q + 25Q = 1975 15Q = 975 Q = 65 making D = 35; Check: does 10 x 35 + 65 x 25 = 1975? 350 + 1625 = 1975. Game over.


How is the best way to remove coins from a piggy bank?

shake the piggy bank until all the coins get out.


A piggy bank has quarters and nickels in it There are eight more nickels than quarters if the total value of the coins is 6.10 how many of each coin are there?

Let X equal the number of quarters X * 25 is the value of the quarters ((X+8) * 5) is the value of the nickels25X + 5X + 40 = 610 so 30X + 40 = 610 .subtract 40 from both sides , divide both sides by 30X = 19There are 19 quarters and 27 nickels in the piggy bank


Marty has a piggy bank that contains 2.25. The piggy bank contains only quarters and dimes. There are twice as many dimes as quarters in the bank. How many dimes are in the piggy bank?

Start by setting out what we know in equations. D = 0.10 Q = 0.25 X(0.10) + Y(0.25) = 2.25 X = 2Y Now, replace the X in the longer equation with its known Y equivalent. 2Y(0.10) + Y(0.25) = 2.25 Multiply out the brackets 0.2Y + 0.25Y = 2.25 Add the Y values together 0.45Y = 2.25 Divide both sides by 0.45 Y = 5 So, now we can replace the Y in the longer equation X(0.10) + 5(0.25) = 2.25 and resolve that X(0.10) + 1.25 = 2.25 X(0.10) = 2.25 - 1.25 X(0.10) = 1.00 X = 10 So, there are ten dimes and five quarters.


A piggy bank has only nickels and dimes in it there are 14 coins worth 0.95. How many nickels and dimes are in the bank?

2 variables with 2 equations. A simultaneous equation problem. d+ n = 14 10d + 5n = 95 Multiply the first equation by -5 -5d + -5n = -70 10d + 5n = 95 add together 5d = 25 d = 5 ◄ plug that in the first equation to find n 5 + n = 14 n = 9 ◄ check 5 dimes plus 9 nickles is 50c+45c=95c ■


You piggy bank has all nickels and quarters. You count up the coins and find out that there are 64 coins and you have a total of 7.40. How many of each type of coin do you have?

The idea is to write two equations, one for the number of coins, one for the amount of money. Then solve the equations.Assuming "n" is the number of nickels, and "q" the number of quarters, the equations for the coins, of course, is quite simply: n + q = 64 And the equation for the money (I'll use cents; you can just as well use dollars if you prefer): 5n + 25q = 740 You can solve the first equation for "n", then replace that in the second equation.


Are coins in a piggy bank an element?

yes


What type of mixture is coins in a piggy bank?

heterogeneous


Why is a piggy bank a piggy?

The origins of the term "piggy bank" come from the Old English word "pygg" which referred to an orange clay. This clay was used to make many things including dishes and jars to hold spare coins. The word pygg sounds much like the word pig, and probably was changed due to misunderstanding. I guess from there, the pygg jar for holding coins became a pig shaped jar, or piggy bank, for holding coins.


What if your piggy bank contains 19.75 in dimes and quarters. There are 100 coins in all. How many dimes are there?

thirty-five 3 x 0.25 = 0.75 and 97 x 0.10 = 9.70 so total 10.45 [wrong] 25 x 0.25 = 6.25 and 75 x 0.10 = 7.50 so total 13.75 [wrong] 41 x 0.25 = 10.25 and 59 x 0.10 = 5.90 so total 16.15 [wrong] 65 x 0.25 = 16.25 and 35 x 0.10 = 3.50 so total 19.75 [correct] Answer: 35 dimes (and 65 quarters)


Can Coins in a piggy bank be considered an element?

No. Coins are not a single metal but alloys. An element can contain only 1 species of molecule.


How much money does your piggy bank have in it?

There is an extremely large amount of possibilities of money combinations that could be within a piggy bank. We must first note that some piggy banks differ in size, but the real problem is with the change itself. The piggy bank could be filled with all pennies, all quarters, 10 dimes and the rest quarters, and so on. The possibilities are limitless.


Which novel contains Ralph Simon and Piggy?

Ralph, Simon and Piggy are major characters in the novel "Lord of the Flies" written by William Golding.


What amount of money is contained in a piggy bank holding 5 pennies and 8 nickels?

8X5=40 and 5X1=5 so $0.45


5 letter word for greedy it contains two g's?

piggy


How many ways are there to choose eight coins from a piggy bank containing 100 identical pennies and 80 identical nickels?

C(8+1, 1)= c(9, 1) = [9!/1!(9-1)!] = [9!/1! 8!] = [9/1!] = 9.


Marty has a piggy bank that contains 2.25 The piggy bank contains only quarters and dimes There are twice as many dimes as quarters in the bank How many dimes are in the piggy bank?

Start by setting out what we know in equations. D = 0.10 Q = 0.25 X(0.10) + Y(0.25) = 2.25 X = 2Y Now, replace the X in the longer equation with its known Y equivalent. 2Y(0.10) + Y(0.25) = 2.25 Multiply out the brackets 0.2Y + 0.25Y = 2.25 Add the Y values together 0.45Y = 2.25 Divide both sides by 0.45 Y = 5 So, now we can replace the Y in the longer equation X(0.10) + 5(0.25) = 2.25 and resolve that X(0.10) + 1.25 = 2.25 X(0.10) = 2.25 - 1.25 X(0.10) = 1.00 X = 10 So, there are ten dimes and five quarters.