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You don't need the mass of the puck to calculate the acceleration.

Acceleration = (change in speed) divided by (time interval) = 6/2 = 3 meters per second2

Since the acceleration of gravity on earth is 9.78 m/s2 , the puck's acceleration was 3/9.78 = 0.307 of one G .

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Q: A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6m s in 2 seconds how much did the hockey puck accelerate?
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Which will go faster a light object thrown with a strong force or a heavy object thrown with a strong force?

A lighter object will achieve a greater acceleration from a given force than a heavier (more massive) object to which the same force is applied.This follows the formula F = ma where F is the force, m the mass of the object, and a the acceleration caused. For the same force F, a larger mass m will accelerate less. (That is, because a = F/m, a larger divisor m results in a smaller a.)A simplified example would be hitting two objects of different mass with a hockey stick : a sliding hockey puck and a skating hockey player. Hitting the puck will cause a considerable increase in its velocity, but hitting the player's back pads will not noticeably change his forward speed.


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If a puck is placed on the ice so that it isn't moving it will stay where it is placed. That's inertia.If a player whacks the puck straight for the net and no other player gets in the way then the puck will go into the net. The only thing that could slow the puck would be the tiny friction between the ice and the puck but that doesn't amount to much. The air turbulence around a puck must have a slight effect too. But the overall straight line trajectory of the puck is inertia too.In ordinary life, things 'at rest stay at rest' and things that are moving move in straight lines unless additional forces act on those things.


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Can you answer show work A hockey puck is sliding along the ice with a constant velocity of 6 m s Its mass is 0 point 5 kg What force must be applied to bring the puck to a complete stop in 2 seconds?

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