The playground is 26 feet long. x= playground length; y= playground width; p= playground perimeter= 94 x= y + 5 Perimeter= 2x + 2y 2x + 2y = 94 2(y+5) + 2y= 94 2y + 10 + 2y= 94 4y + 10= 94 4y= 84 y= 21; x= y +5= 26
yo brotha!
The rectangle would be shaped like any other rectangle. To find the perimeter, add all four sides together. perimeter = 50ft + 50ft + 25ft + 25ft = 150ft
Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards
Two sides will enclose a lenticular (lens shaped) area. Its perimeter is 2.9 + 5.8 = 8.7 units of length.
Perimeter of a rectangle = 2*(H+W) = 2*(11+22) = 2*33 = 66 inches.
LENGTH TIMES THE BREDTH
5000 feet ********** 5000 square feet is the AREA of the park (i.e. length x width). The perimeter is the total distance around the outside edge (i.e. 100 + 50 + 100 + 50), which is 300 feet. Pretty small park!
Only a rectangle.
Depends on the type of piano I guess. Most keyboards are rectangle shaped, there are rectangle/square shaped grand pianos but they are not common, most uprights are rectangle.
For Four sided shaped just Multiply the Length and Width, such as rectangle, square, rhombusetc.
A rhombus has four sides that are equal in length, so the perimeter can be found by multiplying the length of one side by four. Therefore, a rhombus highway sign with a 20 centimeter side has a perimeter of 80 centimeters.
A rhombus has all four sides the same length, so its perimeter is 4 x length_one_side = 4 x 3 cm = 12 cm