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A projectile fired from the ground follows a parabolic path The speed of the projectile is minimum at the top of its path?
Wiki User
∙ 13y ago
Yep that is correct. To understand this it may help you to draw a parabola. If you draw a line from the top of the parabola back to the ground you'd notice either side of this line is symmetrical. This isn't quite what happens to a projectile (following a parabolic path), but because of the nature of the question, effects such as air resistance can be ignored.
As the projectile approaches the top of its path, the vertical component of its velocity approaches zero. As the projectile begins to fall the magnitude of the vertical component of the projectile begins to increase. The only force that acts on the projectile during flight is gravity which pulls it towards the earth. Since this force and the horizontal component of the projectiles velocity are at right angles to each other, the horizontal component of the velocity is unaffected during flight . This explains the symmetry of the parabola and also means the time to reach the top of path equals the time from the top of path back to the ground.
The projectile will hit the ground with the same speed as it left the ground. If you draw a horizontal line through the parabola, at the two points where the line and the parabola cross, the speed of the projectile will be the same. The only change to the balls speed during the flight comes as the vertical component of its velocity tends to zero as it reaches the top of the curve and then falling back down due to gravity.
I'm unsure of your physics knowledge but hopefully this doesn't confuse you. If you have learned about vectors, then this can be simply understood/explained.
Wiki User
∙ 13y ago
Wiki User
∙ 9y agoWhen the projectile attains its highest elevation, it is at its lowest speed. Gravity is a crucial factor that affects the speed of a projectile at a certain altitude.
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Why projectile angle increase when projectile range also increase?
Range of a projectileThe path of this projectile launched from a height y0 has a range d.In physics, a projectile launched with specific initial conditions in a uniform gravity field will have a predictable range. As in Trajectory of a projectile, we will use:g: the gravitational acceleration-usually taken to be 9.80 m/s2 (32 f/s2) near the Earth's surfaceθ: the angle at which the projectile is launchedv: the velocity at which the projectile is launchedy0: the initial height of the projectiled: the total horizontal distance travelled by the projectileWhen neglecting air resistance, the range of a projectile will beIf (y0) is taken to be zero, meaning the object is being launched on flat ground, the range of the projectile will then simplify toso to increase the range θ shoud vary from 0 to 45 and after 45 it starts decreasing.
How does the first Law of Motion relate to the catapult?
All three play a part. The first applies as the arm swings and launches the projectile. The arm continues to move until it is stopped by the retaining bar and the projectile continues to move until gravity pulls back down or it impacts a structure. The second law is shown by the projectile. A big heavy rock goes slow, a small light rock flies fast. The third comes into play as the catapult launches the projectile it pushes down on the ground and slightly backward. The projectile itself uses the third law when it impacts.
What is the minimum ground wire size for a 20 amp 110 volt circuit?
The ground wire in a two or three conductor #12 cable is a #14 bare ground wire.
How far from the ground do you have to be when you are running electrical wire in the walls of an unfinished basement?
There is no minimum. It only has to be protected from damage.
What is the minimum distance a ground fault device should be installed near a water source?
15 feet.
Is a ball on the ground a projectile?
No.
How will a ball falling fom train appear to a passenger on train and a man standing on ground?
To a passenger on the train it will follow a parabolic trajectory facing towards the back of the train. To a man standing on the ground it will be a forward facing parabolic trajectory.
With out air pressure at what point or points in its path does a projectile have its minimum speed and its maximum?
Without air friction, the horizontal component of the velocity will be constant. The vertical component of the velocity will be a maximum at the lowest point in its motion and at a minimum at the highest point in its motion. Therefore the minimum is at the highest point in its motion- Potential energy max Kinetic Energy min and the maximum is at its lowest point in the motion- KE is max PE min
What is the projectile theory?
if a body is thrown having initial velocity and make angle with ground this body is known as projectile and the way is calle trajectory
Which information is needed to determine the horizontal distance a projectile travels?
-- the initial horizontal speed of the projectile -- the time it remains in flight before it hits the ground
How is acceleration described as the projectile rises and then falls back to the ground?
acceleration remains the same
How do you draw a horizontal?
It's parabolic. More specifically, it's half a parabola, with a vertex at the point of origin. You see, horizontal and vertical velocity are independent of each other. This means that the projectile will more horizontally at a constant velocity (ignoring wind resistance) equal to its initial velocity. At the same time, the projectile is accelerated downward at a rate of 9.8 m/s2 (approximately). Since it undergoes constant acceleration, it increases in velocity every second exponentially, giving it a parabolic curve. As an interesting side note, since horizontal and vertical velocity are always independent of each other, any velocity (really, any vector) can be represented as its horizontal and vertical components, allowing one to add up the individual components and to find a resultant vector quantity. Here's an example drawing of the curve described: http://www.staff.amu.edu.pl/~romangoc/graphics/M2/1-projectile-motion/M2-3.gif Keep in mind that if the point of origin is at a greater vertical level than the ground, the projectile will fall all the way to the ground, past the horizontal axis.
Why a small departure from 45 degree landing angle can reduce the horizontal range?
The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
What is the opposite of crater?
There is no "opposite" of crater. A crater is formed by a high speed projectile hitting the ground, spewing matter outwards, creating a rim and a depression. The opposite would be a high speed projectile, leaving the ground and forming a hill. If you'd said depression, I'd have said a hill.
The horizontal speed of a projectile launched over flat ground will affect the time that the projectile will stay in the air is this true or false?
this is false. the horizontal speed of the object has absolutely nothing to do with how long it takes to fall. if you fire a bullet on level ground it will hit the ground at the same time an apple would if you drop it from the same distance above the ground at the same time. the force of gravity is the same on everything on earth.
What energy transformation takes place as the catapult is launced?
A catapult is used to throw things. If, for example, you look at the trebuchet, you see that it has a very heavy load, heavier then the projectile, that is set up above the ground. This gives the load and consequentially the trebuchet a lot of potential energy. The projectile is launched when the load starts to fall on the ground, when it's falling, it gets kinetic energy which is given to the projectile. The projectile uses it to build up potential energy as it flies towards it's goal, and then gains back the kinetic energy as it falls.
How do you dig a hole without digging?
You could shoot a hole into the ground without digging just has to a very powerful projectile
