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A projectile is shot from the edge of a cliff h 225 m above ground level with an initial speed of v0 135 ms at an angle of 37.0 with the horizontal(a) Determine the time taken by the projectile?
Dylanatto
Initial speed in vertical direction = 135 sin 37
Total distance traversed in vertical direction = -225 m
Acceleration due to gravity = - 9.8 m/s^2
Applying s = ut + 1/2 g t^2
-225 = 135 sin 37 t - 4.9 t^2
But sin 37 = 0.6 approx
So 4.9 t^2 - 81 t + 225 = 0
Solving quadratic equation you can get the value of t as (1/4.9) * (+81+46.4) = 26 s OR 7 s
7 s is not suitable practically.
Hence time of traverse = 26 s
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No.
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42
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