5
y = 0
y = x
y = -x + 5
Let's find the intersection point of the lines with equation y = x and y = -x + 5.
y = x
y = -x + 5 (add both equations)
2y = 5(divide by 2 both sides)
y = 5/2 = 2.5 which yields that x = 2.5.
So the intersection point (2.5, 2.5) tells us that the right triangle is an isosceles triangle, because the altitude drawn from the point of intersection to the side (with a length of 5 since the y-intercept of y = -x + 5, is 5) that lies on y = 0, separates it in two equal parts of 2.5.
Since the altitude and the base of this right triangle are congruent, we can find their lengths by using the distance formula between two points (0, 0) and (2.5, 2.5) or using sin 45 degrees, which gives us the same result for a length of 3.536.
So the are of the triangle equals to 3.5362/2= 6.25 unit squares.
It is 8*sqrt(2)/3 = 3.7712 approx.
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
yes!
39.0625 is.
The first.
It is 8*sqrt(2)/3 = 3.7712 approx.
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
yes!
39.0625 is.
The first.
right upper quadrant
The first quadrant.
(0-5) lies in First Quadrant
The first quadrant is the quarter if the infinite plane where for every point, the 'x' and 'y' coordinates are both positive.
Converse: If the coordinates are positive, then the point is in the first quadrant
As shown in the picture, the first quadrant is the top right corner of the coordinate plane.
In the second quadrant.